Convert SVG to transparent PNG with antialiasing, using ImageMagick

Question

I want to convert SVG images to PNG files with transparent background and anti-aliased edges (using semi-transparent pixels). Unfortunately I can\'t get ImageMagick to do th

Answer 1

I add a rect as background. The embed CSS hide the background. Then I catch its color for setting the transparent attribute of ImageMagick.

---

SVG file:

<?xml version="1.0" ?>
<!DOCTYPE svg  PUBLIC '-//W3C//DTD SVG 1.1//EN'  'http://www.w3.org/Graphics/SVG/1.1/DTD/svg11.dtd'>
<svg 
    version="1.1" xml:space="preserve" xmlns="http://www.w3.org/2000/svg" xmlns:xlink="http://www.w3.org/1999/xlink"
    width="500px" height="500px"
    viewBox="0 0 500 500" 
    enable-background="new 0 0 500 500" 
    >
<defs>
    <style>
        #background { display: none; }
    </style>
</defs>
<rect id="background" x="0" y="0" width="500" height="500" fill="#e8e437"/>
<!-- beginning of the sketch -->
<g fill="#000" text-anchor="middle"font-size="112">
    <text y="350" x="192">OK</text>
</g>
<!-- end of the sketch -->
</svg>

---

bash script

#!/bin/bash


BASE_DIR=$( cd "$( dirname "${BASH_SOURCE[0]}" )" >/dev/null && pwd )
SVG_DIR="$BASE_DIR/import"
PNG_DIR="$BASE_DIR/export"

for f in `ls $SVG_DIR/*.svg`
do
    g="$PNG_DIR/$(basename "$f" .svg).png"
    BGCOLOR=`grep 'id="background"' $f \
        | sed 's/.* fill="\([^"]*\)".*/\1/'`

    convert $f -transparent "$BGCOLOR" $g
done

Answer 2

The way I learned how to do this was from the methodology found here: How to convert a .eps file to a high quality 1024x1024 .jpg?

It is the same idea as @halfer's solution with inkscape--to jack up the DPI first--but you can accomplish the same thing in just imagemagick using the -density option.

convert -density 200 in.svg -resize 25x25 -transparent white out.png