I need different constructors for my instances. What is a common pattern for that?
How do you find this one?
function Foobar(foobar) {
this.foobar = foobar;
}
Foobar.prototype = {
foobar: null
};
Foobar.fromComponents = function(foo, bar) {
var foobar = foo + bar;
return new Foobar(foobar);
};
//usage: the following two lines give the same result
var x = Foobar.fromComponents('Abc', 'Cde');
var y = new Foobar('AbcDef')
Didn't feel like doing it by hand as in bobince's answer, so I just completely ripped off jQuery's plugin options pattern.
Here's the constructor:
//default constructor for Preset 'class'
function Preset(params) {
var properties = $.extend({
//these are the defaults
id: null,
name: null,
inItems: [],
outItems: [],
}, params);
console.log('Preset instantiated');
this.id = properties.id;
this.name = properties.name;
this.inItems = properties.inItems;
this.outItems = properties.outItems;
}
Here's different ways of instantiation:
presetNoParams = new Preset();
presetEmptyParams = new Preset({});
presetSomeParams = new Preset({id: 666, inItems:['item_1', 'item_2']});
presetAllParams = new Preset({id: 666, name: 'SOpreset', inItems: ['item_1', 'item_2'], outItems: ['item_3', 'item_4']});
And here's what that made:
presetNoParams
Preset {id: null, name: null, inItems: Array[0], outItems: Array[0]}
presetEmptyParams
Preset {id: null, name: null, inItems: Array[0], outItems: Array[0]}
presetSomeParams
Preset {id: 666, name: null, inItems: Array[2], outItems: Array[0]}
presetAllParams
Preset {id: 666, name: "SOpreset", inItems: Array[2], outItems: Array[2]}
JavaScript doesn't have function overloading, including for methods or constructors.
If you want a function to behave differently depending on the number and types of parameters you pass to it, you'll have to sniff them manually. JavaScript will happily call a function with more or fewer than the declared number of arguments.
function foo(a, b) {
if (b===undefined) // parameter was omitted in call
b= 'some default value';
if (typeof(a)==='string')
this._constructInSomeWay(a, b);
else if (a instanceof MyType)
this._constructInSomeOtherWay(a, b);
}
You can also access arguments
as an array-like to get any further arguments passed in.
If you need more complex arguments, it can be a good idea to put some or all of them inside an object lookup:
function bar(argmap) {
if ('optionalparam' in argmap)
this._constructInSomeWay(argmap.param, argmap.optionalparam);
...
}
bar({param: 1, optionalparam: 2})
Python demonstrates how default and named arguments can be used to cover the most use cases in a more practical and graceful way than function overloading. JavaScript, not so much.
Going further with eruciform's answer, you can chain your new
call into your init
method.
function Foo () {
this.bar = 'baz';
}
Foo.prototype.init_1 = function (bar) {
this.bar = bar;
return this;
};
Foo.prototype.init_2 = function (baz) {
this.bar = 'something to do with '+baz;
return this;
};
var a = new Foo().init_1('constructor 1');
var b = new Foo().init_2('constructor 2');
export default class Order {
static fromCart(cart) {
var newOrder = new Order();
newOrder.items = cart.items;
newOrder.sum = cart.sum;
return newOrder;
}
static fromOrder(id, order) {
var newOrder = new Order();
newOrder.id = id;
newOrder.items = order.items;
newOrder.sum = order.sum;
return newOrder;
}
}
Useges:
var newOrder = Order.fromCart(cart)
var newOrder = Order.fromOrder(id, oldOrder)
Answering because this question is returned first in google but the answers are now outdated.
You can use Destructuring objects as constructor parameters in ES6
Here's the pattern:
You can't have multiple constructors, but you can use destructuring and default values to do what you want.
export class myClass {
constructor({ myArray = [1, 2, 3], myString = 'Hello World' }) {
// ..
}
}
And you can do this if you want to support a 'parameterless' constructor.
export class myClass {
constructor({myArray = [1, 2, 3], myString = 'Hello World'} = {}) {
// ..
}
}