Unix ls command: show full path when using options

Question

I often use this list command in Unix (AIX / KSH):

ls -Artl

It displays the files as this:

-rw-r--r-- 1 myuser mygroup 0 Apr 2

Answer 1

Use this command:

ls -ltr /mig/mthome/09/log/*

instead of:

ls -ltr /mig/mthome/09/log

to get the full path in the listing.

Answer 2

I use this command:

ls -1 | xargs readlink -f

Answer 3

You can combine the find command and the ls command. Use the path (.) and selector (*) to narrow down the files you're after. Surround the find command in back quotes. The argument to -name is doublequote star doublequote in case you can't read it.

ls -lart `find . -type f -name "*" `

Answer 4

Try this, works for me: ls -d /a/b/c/*

Answer 5

I wrote a shell script called fullpath that contains this code, use it everyday:

    #!/bin/sh
    for i in $* ; do
        echo $(pwd)/$i
    done

Put it somewhere in your PATH, and make it executable(chmod 755 fullpath) then just use
fullpath file_or_directory

Answer 6

optimized from spacedrop answer ...

ls $(pwd)/*

and you can use ls options

ls -alrt $(pwd)/*