How to remove specific substrings from a set of strings in Python?

Question

I have a set of strings set1, and all the strings in set1 have a two specific substrings which I don\'t need and want to remove.
Sample Input

Answer 1

You could do this:

import re
import string
set1={'Apple.good','Orange.good','Pear.bad','Pear.good','Banana.bad','Potato.bad'}

for x in set1:
    x.replace('.good',' ')
    x.replace('.bad',' ')
    x = re.sub('\.good$', '', x)
    x = re.sub('\.bad$', '', x)
    print(x)

Answer 2

I did the test (but it is not your example) and the data does not return them orderly or complete

>>> ind = ['p5','p1','p8','p4','p2','p8']
>>> newind = {x.replace('p','') for x in ind}
>>> newind
{'1', '2', '8', '5', '4'}

I proved that this works:

>>> ind = ['p5','p1','p8','p4','p2','p8']
>>> newind = [x.replace('p','') for x in ind]
>>> newind
['5', '1', '8', '4', '2', '8']

or

>>> newind = []
>>> ind = ['p5','p1','p8','p4','p2','p8']
>>> for x in ind:
...     newind.append(x.replace('p',''))
>>> newind
['5', '1', '8', '4', '2', '8']

Answer 3

All you need is a bit of black magic!

>>> a = ["cherry.bad","pear.good", "apple.good"]
>>> a = list(map(lambda x: x.replace('.good','').replace('.bad',''),a))
>>> a
['cherry', 'pear', 'apple']

Answer 4

if you delete something from list , u can use this way : (method sub is case sensitive)

new_list = []
old_list= ["ABCDEFG","HKLMNOP","QRSTUV"]

for data in old_list:
     new_list.append(re.sub("AB|M|TV", " ", data))

print(new_list) // output : [' CDEFG', 'HKL NOP', 'QRSTUV']