How do I get the find command to print out the file size with the file name?

Question

If I issue the find command as follows:

$ find . -name *.ear

It prints out:

./dir1/dir2/earFile1.ear
./dir1/dir2/earFile2.         


        

Answer 1

If you need to get total size, here is a script proposal

#!/bin/bash
totalSize=0

allSizes=`find . -type f -name *.ear -exec stat -c "%s" {} \;`

for fileSize in $allSizes; do
    totalSize=`echo "$(($totalSize+$fileSize))"`
done
echo "Total size is $totalSize bytes"

Answer 2

find . -name '*.ear' -exec du -h {} \;

This gives you the filesize only, instead of all the unnecessary stuff.

Answer 3

This should get you what you're looking for, formatting included (i.e. file name first and size afterward):

find . -type f -iname "*.ear" -exec du -ah {} \; | awk '{print $2"\t", $1}'

sample output (where I used -iname "*.php" to get some result):

./plugins/bat/class.bat.inc.php  20K
./plugins/quotas/class.quotas.inc.php    8.0K
./plugins/dmraid/class.dmraid.inc.php    8.0K
./plugins/updatenotifier/class.updatenotifier.inc.php    4.0K
./index.php      4.0K
./config.php     12K
./includes/mb/class.hwsensors.inc.php    8.0K

Answer 4

Try the following commands:

GNU stat:

find . -type f -name *.ear -exec stat -c "%n %s" {} ';'

BSD stat:

find . -type f -name *.ear -exec stat -f "%N %z" {} ';'

however stat isn't standard, so du or wc could be a better approach:

find . -type f -name *.ear -exec sh -c 'echo "{} $(wc -c < {})"' ';'

Answer 5

You could try this:

find. -name *.ear -exec du {} \;

This will give you the size in bytes. But the du command also accepts the parameters -k for KB and -m for MB. It will give you an output like

5000  ./dir1/dir2/earFile1.ear
5400  ./dir1/dir2/earFile2.ear
5400  ./dir1/dir3/earFile1.ear

Answer 6

$ find . -name "test*" -exec du -sh {} \;
4.0K    ./test1
0       ./test2
0       ./test3
0       ./test4
$

Scripter World reference