How to check if a network port is open on linux?

Question

How can I know if a certain port is open/closed on linux ubuntu, not a remote system, using python? How can I list these open ports in python?

• Netstat: Is th

Answer 1

If you only care about the local machine, you can rely on the psutil package. You can either:

1. Check all ports used by a specific pid:

   proc = psutil.Process(pid)
   print proc.connections()
   

2. Check all ports used on the local machine:

   print psutil.net_connections()
   

It works on Windows too.

https://github.com/giampaolo/psutil

Answer 2

Here's a fast multi-threaded port scanner:

from time import sleep
import socket, ipaddress, threading

max_threads = 50
final = {}
def check_port(ip, port):
    try:
        sock = socket.socket(socket.AF_INET, socket.SOCK_STREAM) # TCP
        #sock = socket.socket(socket.AF_INET, socket.SOCK_DGRAM) # UDP
        socket.setdefaulttimeout(2.0) # seconds (float)
        result = sock.connect_ex((ip,port))
        if result == 0:
            # print ("Port is open")
            final[ip] = "OPEN"
        else:
            # print ("Port is closed/filtered")
            final[ip] = "CLOSED"
        sock.close()
    except:
        pass
port = 80
for ip in ipaddress.IPv4Network('192.168.1.0/24'): 
    threading.Thread(target=check_port, args=[str(ip), port]).start()
    #sleep(0.1)

# limit the number of threads.
while threading.active_count() > max_threads :
    sleep(1)

print(final)

---

Live Demo

Answer 3

For me the examples above would hang if the port wasn't open. Line 4 shows use of settimeout to prevent hanging

import socket

sock = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
sock.settimeout(2)                                      #2 Second Timeout
result = sock.connect_ex(('127.0.0.1',80))
if result == 0:
  print 'port OPEN'
else:
  print 'port CLOSED, connect_ex returned: '+str(result)

Answer 4

You can using the socket module to simply check if a port is open or not.

It would look something like this.

import socket
sock = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
result = sock.connect_ex(('127.0.0.1',80))
if result == 0:
   print "Port is open"
else:
   print "Port is not open"
sock.close()

Answer 5

Please check Michael answer and vote for it. It is the right way to check open ports. Netstat and other tools are not any use if you are developing services or daemons. For instance, I am crating modbus TCP server and client services for an industrial network. The services can listen to any port, but the question is whether that port is open? The program is going to be used in different places, and I cannot check them all manually, so this is what I did:

from contextlib import closing
import socket
class example:
    def __init__():

       self.machine_ip = socket.gethostbyname(socket.gethostname())
       self.ready:bool = self.check_socket()

    def check_socket(self)->bool:
        result:bool = True
        with closing(socket.socket(socket.AF_INET, socket.SOCK_STREAM)) as sock:
        modbus_tcp_port:int = 502
        if not sock.connect_ex((self.machine_ip, modbus_tcp_port)) == 0:
            result = False
        return result

Answer 6

Just added to mrjandro's solution a quick hack to get rid of simple connection errors / timeouts.

You can adjust the threshold changing max_error_count variable value and add notifications of any sort.

import socket

max_error_count = 10

def increase_error_count():
    # Quick hack to handle false Port not open errors 
    with open('ErrorCount.log') as f:
        for line in f:
            error_count = line
    error_count = int(error_count)
    print "Error counter: " + str(error_count)
    file = open('ErrorCount.log', 'w')
    file.write(str(error_count + 1))
    file.close()
    if error_count == max_error_count:
        # Send email, pushover, slack or do any other fancy stuff
        print "Sending out notification"
        # Reset error counter so it won't flood you with notifications
        file = open('ErrorCount.log', 'w')
        file.write('0')
        file.close()

sock = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
sock.settimeout(2) 
result = sock.connect_ex(('127.0.0.1',80))
if result == 0:
        print "Port is open"
else:
        print "Port is not open"
        increase_error_count()

And here you find a Python 3 compatible version (just fixed print syntax):

import socket

max_error_count = 10

def increase_error_count():
    # Quick hack to handle false Port not open errors
    with open('ErrorCount.log') as f:
        for line in f:
            error_count = line
    error_count = int(error_count)
    print ("Error counter: " + str(error_count))
    file = open('ErrorCount.log', 'w')
    file.write(str(error_count + 1))
    file.close()
    if error_count == max_error_count:
        # Send email, pushover, slack or do any other fancy stuff
        print ("Sending out notification")
        # Reset error counter so it won't flood you with notifications
        file = open('ErrorCount.log', 'w')
        file.write('0')
        file.close()

sock = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
sock.settimeout(2) 
result = sock.connect_ex(('127.0.0.1',80))
if result == 0:
        print ("Port is open")
else:
        print ("Port is not open")
        increase_error_count()