Get specific object by id from array of objects in AngularJS

Question

I have a JSON file containing some data I d like to access on my AngularJS website. Now what I want is to get only one object from the array. So I d like for example Item wi

Answer 1

    projectDetailsController.controller('ProjectDetailsCtrl', function ($scope, $routeParams, $http) {
    $http.get('data/projects.json').success(function(data) {

        $scope.projects = data;
        console.log(data);

        for(var i = 0; i < data.length; i++) {
        $scope.project = data[i];
        if($scope.project.name === $routeParams.projectName) {
            console.log('project-details',$scope.project);
        return $scope.project;
        }
        }

    });
});

Not sure if it's really good, but this was helpful for me.. I needed to use $scope to make it work properly.

Answer 2

If you want the list of items like city on the basis of state id then use

var state_Id = 5;
var items = ($filter('filter')(citylist, {stateId: state_Id }));

Answer 3

I would iterate over the results array using an angularjs filter like this:

var foundResultObject = getObjectFromResultsList(results, 1);

function getObjectFromResultsList(results, resultIdToRetrieve) {
        return $filter('filter')(results, { id: resultIdToRetrieve }, true)[0];
    }

Answer 4

use $timeout and run a function to search in "results" array

app.controller("Search", function ($scope, $timeout) {
        var foo = { "results": [
          {
             "id": 12,
             "name": "Test"
          },
          {
             "id": 2,
             "name": "Beispiel"
          },
          {
             "id": 3,
            "name": "Sample"
          }
        ] };
        $timeout(function () {
            for (var i = 0; i < foo.results.length; i++) {
                if (foo.results[i].id=== 2) {
                    $scope.name = foo.results[i].name;
                }
            }
        }, 10);

    });

Answer 5

The simple way to get (one) element from array by id:

The find() method returns the value of the first element in the array that satisfies the provided testing function. Otherwise undefined is returned.

function isBigEnough(element) {
    return element >= 15;
}

var integers = [12, 5, 8, 130, 160, 44];
integers.find(isBigEnough); // 130  only one element - first

you don't need to use filter() and catch first element xx.filter()[0] like in comments above

The same for objects in array

var foo = {
"results" : [{
    "id" : 1,
    "name" : "Test"
}, {
    "id" : 2,
    "name" : "Beispiel"
}, {
    "id" : 3,
    "name" : "Sample"
}
]};

var secondElement = foo.results.find(function(item){
    return item.id == 2;
});

var json = JSON.stringify(secondElement);
console.log(json);

Of course if you have multiple id then use filter() method to get all objects. Cheers

function isBigEnough(element) {
    return element >= 15;
}

var integers = [12, 5, 8, 130, 160, 44];
integers.find(isBigEnough); // 130  only one element - first

var foo = {
"results" : [{
    "id" : 1,
    "name" : "Test"
}, {
    "id" : 2,
    "name" : "Beispiel"
}, {
    "id" : 3,
    "name" : "Sample"
}
]};

var secondElement = foo.results.find(function(item){
    return item.id == 2;
});

var json = JSON.stringify(secondElement);
console.log(json);