I have an array that I\'ve created in TypeScript and it has a property that I use as a key. If I have that key, how can I remove an item from it?
One more solution using Typescript:
let updatedArray = [];
for (let el of this.oldArray) {
if (el !== elementToRemove) {
updated.push(el);
}
}
this.oldArray = updated;
Answer using TypeScript spread operator (...)
// Your key
const key = 'two';
// Your array
const arr = [
'one',
'two',
'three'
];
// Get either the index or -1
const index = arr.indexOf(key); // returns 0
// Despite a real index, or -1, use spread operator and Array.prototype.slice()
const newArray = (index > -1) ? [
...arr.slice(0, index),
...arr.slice(index + 1)
] : arr;
Just wanted to add extension method for an array.
interface Array<T> {
remove(element: T): Array<T>;
}
Array.prototype.remove = function (element) {
const index = this.indexOf(element, 0);
if (index > -1) {
return this.splice(index, 1);
}
return this;
};
Here's a simple one liner for removing an object by property from an array of objects.
delete this.items[this.items.findIndex(item => item.item_id == item_id)];
or
this.items = this.items.filter(item => item.item_id !== item.item_id);
Use this, if you need to remove a given object from an array and you want to be sure of the following:
const objWithIdToRemove;
const objIndex = this.objectsArray.findIndex(obj => obj.id === objWithIdToRemove);
if (objIndex > -1) {
this.objectsArray.splice(objIndex, 1);
}
let a: number[] = [];
a.push(1);
a.push(2);
a.push(3);
let index: number = a.findIndex(a => a === 1);
if (index != -1) {
a.splice(index, 1);
}
console.log(a);