How to count number of files in each directory?

Question

I am able to list all the directories by

find ./ -type d

I attempted to list the contents of each directory and count the number of files i

Answer 1

find . -type f | cut -d/ -f2 | sort | uniq -c

• find. -type f to find all items of the type file
• cut -d/ -f2 to cut out their specific folder
• sort to sort the list of foldernames
• uniq -c to return the number of times each foldername has been counted

Answer 2

Slightly modified version of Sebastian's answer using find instead of du (to exclude file-size-related overhead that du has to perform and that is never used):

 find ./ -mindepth 2 -type f | cut -d/ -f2 | sort | uniq -c | sort -nr

-mindepth 2 parameter is used to exclude files in current directory. If you remove it, you'll see a bunch of lines like the following:

  234 dir1
  123 dir2
    1 file1
    1 file2
    1 file3
      ...
    1 fileN

(much like the du-based variant does)

If you do need to count the files in current directory as well, use this enhanced version:

{ find ./ -mindepth 2 -type f | cut -d/ -f2 | sort && find ./ -maxdepth 1 -type f | cut -d/ -f1; } | uniq -c | sort -nr

The output will be like the following:

  234 dir1
  123 dir2
   42 .

Answer 3

I tried with some of the others here but ended up with subfolders included in the file count when I only wanted the files. This prints ./folder/path<tab>nnn with the number of files, not including subfolders, for each subfolder in the current folder.

for d in `find . -type d -print` 
do 
  echo -e "$d\t$(find $d -maxdepth 1 -type f -print | wc -l)"
done

Answer 4

This should return the directory name followed by the number of files in the directory.

findfiles() {
    echo "$1" $(find "$1" -maxdepth 1 -type f | wc -l)
}

export -f findfiles

find ./ -type d -exec bash -c 'findfiles "$0"' {} \;

Example output:

./ 6
./foo 1
./foo/bar 2
./foo/bar/bazzz 0
./foo/bar/baz 4
./src 4

The export -f is required because the -exec argument of find does not allow executing a bash function unless you invoke bash explicitly, and you need to export the function defined in the current scope to the new shell explicitly.

Answer 5

THis could be another way to browse through the directory structures and provide depth results.

find . -type d  | awk '{print "echo -n \""$0"  \";ls -l "$0" | grep -v total | wc -l" }' | sh