How to join every sublist to a single string in Python?

Question

MWE: Here is the list :

L=[[\'1\', \'1\', \'0\', \'0\', \'0\'],[\'1\', \'1\', \'1\', \'1\', \'0\'],[\'0\', \'0\', \'1\', \'1\', \'0\']]
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Answer 1

flat list can be made through reduce easily.

All you need to use initializer - third argument in the reduce function.

reduce(
   lambda result, _list: result.append(''.join(_list)) or result, 
   L, 
   [])

or map and reduce in combination,

import operator
map(lambda l: reduce(operator.iconcat, l), L)

Above code works for both python2 and python3, but you need to import reduce module as from functools import reduce. Refer below link for details.

• for python2

• for python3

Answer 2

You can either use a list comprehension:

L = [
    ['1', '1', '0', '0', '0'],
    ['1', '1', '1', '1', '0'],
    ['0', '0', '1', '1', '0']
    ]

D = [''.join(l) for l in L]

or the map function:

D = map(''.join, L) # returns a generator in python3, cast it to list to get one

Note that the most pythonic way of doing this is the list comprehension.

Answer 3

L = [['1', '1', '0', '0', '0'],['1', '1', '1', '1', '0'],['0', '0', '1', '1', '0']]
D = [''.join(sub_list) for sub_list in L]