I need to use windows file path to do some operation on files but i am getting invalid escape sequence error.
File f = new File(\"C:\\test\");
Use java.nio.file.Path instead of java.io, you'll not have problem with escape sequence character :
import java.nio.file.Path;
import java.nio.file.Paths;
Path path = Paths.get("C:\test");
\ is the escape character in Java Strings. Use \\ instead.
"C:\\test" resolves to the String C:\test
File f = new File("C:\\test"); is correct.
You are not creating a File with the path "C:\\test" here. You are creating a File with the path "C:\test". The \\-to-\ conversion happens when you compile the program - by the time your program is running, the double backslashes are gone.
The same for String - String s = "C:\\test"; does not create a string with two backslashes, only one.
You can think of it this way: the string does not actually have two backslashes, but you have to write it that way to put it in your code.
You might be wondering why that is - it's because backslashes are used to insert special characters in strings. When you type \t in a string it inserts a tab, for example. If you want to insert a backslash, then t, you type \\t.
You can use \\ or / but / is better because it is OS-independent.
Replace the single backslash in the path with a double backslash or a single forward slash to solve your issue.
Internally, Java will convert it to the file seperator of the OS
Use File.seperator in place of "\".
File f = new File("C:"+File.seperator+"test");
File.seperator returns "\" and it is not treated as an escape character.
If your file test.txt is saved in folder D:/MyFloder/MyPrograms you can do something like this
File f = new File("D:"+File.seperator+"MyFloder"+File.seperator+"MyPrograms"+File.seperator+"test.txt");
EDIT
You don't need to worry about OS
For Unix : File.separator = /
For Windows : File.separator = \
you can use '/' (as in Linux) in paths since Windows XP, so forget about \