os.path.isfile() doesn't work. Why?

Question

I\'m trying to do this:

import os
[x for x in os.listdir(\'.\') if os.path.isfile(x)]
[x for x in os.listdir(\'dirname\') if os.path.isfile(x)]
[x for x in o         


        

Answer 1

Because you need to join the dirname with x , os.listdir() just lists the contents directly, the contents do not have full path.

Example -

[x for x in os.listdir('dirname') if os.path.isfile(os.path.join('dirname',x))]

When the full path is not given, os.path.isfile() searches in the current directory, hence when you give '.' to os.listdir() you get a correct list back.

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Example -

Lets say some folder - /a/b/c - has files - x and y in it.

when you do - os.listdir('/a/b/c') , the list returned looks like -

['x','y']

Even if you give absolute path inside os.listdir() , the files returned in the list would have relative path to the dir. You would manually need to join dir and x to get the correct results.

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In your third example, it does not work because os.path.abspath() also works with current directory, so if you do something like -

os.path.abspath('somefile')

The result produced would be - /path/to/current/directory/somefile - it does not validate if that is a real file/dir or not.

It is clearly stated in the documentation (Emphasis mine) -

os.path.abspath(path)

Return a normalized absolutized version of the pathname path. On most platforms, this is equivalent to calling the function normpath() as follows: normpath(join(os.getcwd(), path)).

where os.getcwd() returns the path to current working directory.

Answer 2

isfile() is looking in the current directory. Unless you include the directory name with the file name it has no idea where to find your files.