I have a problem with opening .csv files with Excel by VBA code. I have data organised like:
Number;Name;Price1;Price2;City
1234;\"John Smith\";\"1,75 EUR\"
I hope you are using something newer than Excel 2000. This is what I experience with Excel 2016 on a machine with German format settings: Apparently the Workbooks.Open options for delimiters (Format and Delimiter) are only applied when you open a .txt file. If Local is set to False (the default value), the file will be opened with the VBA language settings, using a comma as delimiter. Setting Local:=True will prevent this so
Workbooks.Open FileName:=strPath & "thisFile.csv", Local:=True
should work for you. If you rename your file to .txt, you can use the Format and Delimiter options:
Workbooks.Open FileName:=strPath & "thisFile.txt", Format:=4 'Format = 4 is semicolon delimited
Workbooks.Open FileName:=strPath & "thisFile.txt", Format:=6, Delimiter:=";" 'Format = 6 is custom delimited
See MSDN for more details
However this will mess up your decimal numbers, see my edit.
Edit: I misread the documentation. The Format and Delimiter options are actually only applied when using a .txt file and not .csv (even the .OpenText method behaves that way).
If you want to make sure it opens on a machine with different format settings the only solution I have right now is to rename it to .txt and use
Workbooks.OpenText Filename:=FileName:=strPath & "thisFile.txt", DataType:=xlDelimited, Semicolon:=True, DecimalSeparator:=",", ThousandsSeparator:="."