I am pretty sure this is quite simple, but seem to have got stuck...I have two xts vectors that have been merged together, which contain numeric values and NAs.
I wo
If you have a variable number of columns you could try this approach:
mm <- merge(dd1,dd2)
mm$m <- rowSums(mm, na.rm=TRUE) * ifelse(rowSums(is.na(mm)) == ncol(mm), NA, 1)
# or, as @JoshuaUlrich commented:
#mm$m <- ifelse(apply(is.na(mm),1,all),NA,rowSums(mm,na.rm=TRUE))
tail(mm, 10)
# dd1 dd2 m
#2013-08-02 NA NA NA
#2013-08-03 NA NA NA
#2013-08-04 NA NA NA
#2013-08-05 1.2542692 -1.2542692 0.000000
#2013-08-06 NA 1.3325804 1.332580
#2013-08-07 NA 0.7726740 0.772674
#2013-08-08 0.8158402 -0.8158402 0.000000
#2013-08-09 NA 1.2292919 1.229292
#2013-08-10 NA NA NA
#2013-08-11 NA 0.9334900 0.933490
My solution would be
library(magrittr)
mm <- mm %>%
transform(ccardNA = rowSums(!is.na(.))/rowSums(!is.na(.)), m = rowSums(., na.rm = TRUE)) %>%
transform(m = ifelse(is.nan(ccardNA), NA, m), ccardNA = NULL) %>%
as.xts()
Use logical indexing with [
and is.na(·)
to localize the entries where both are NA
and then replace them with NA
.
Try this:
> mm[is.na(mm$dd1) & is.na(mm$dd2), "m"] <- NA
> mm
dd1 dd2 m
2013-08-02 NA NA NA
2013-08-03 NA NA NA
2013-08-04 NA NA NA
2013-08-05 1.2542692 -1.2542692 0.000000
2013-08-06 NA 1.3325804 1.332580
2013-08-07 NA 0.7726740 0.772674
2013-08-08 0.8158402 -0.8158402 0.000000
2013-08-09 NA 1.2292919 1.229292
2013-08-10 NA NA NA
2013-08-11 NA 0.9334900 0.933490
mm$m <- "is.na<-"(rowSums(mm, na.rm = TRUE), !rowSums(!is.na(mm)))
> tail(mm)
# dd1 dd2 m
# 2013-08-06 NA 1.3325804 1.332580
# 2013-08-07 NA 0.7726740 0.772674
# 2013-08-08 0.8158402 -0.8158402 0.000000
# 2013-08-09 NA 1.2292919 1.229292
# 2013-08-10 NA NA NA
# 2013-08-11 NA 0.9334900 0.933490