If a user enters a string: hello there
it should output
Hello has 2 vowels
There has 3 consonants.
I know this is a f
Made something like this hope this helps, this will give vowels,consonants of each word
public static void main (String args[])
{
Scanner stdin = new Scanner(System.in);
String string1;
System.out.println("Enter a string");
string1 = stdin.nextLine();
string1 = string1.toLowerCase();
int count = 0;
int vowels = 0;
int consonants = 0;
for (String retval: string1.split(" ")){
for (int i = 0; i < retval.length(); i++)
{
char ch = retval.charAt(i);
if (ch == 'a' || ch == 'e' || ch == 'i' ||
ch == 'o' || ch == 'u')
{
vowels++;
}
else
{
consonants++;
}
}
System.out.println(retval.substring(0, 1).toUpperCase() + retval.substring(1)+" has "+vowels+" vowels and "+consonants+" cosonants");
vowels=0;
consonants=0;
}
}
Here is a simpler way of doing this, hope this helps:
public static void checkVowels(String s){
System.out.println("Vowel Count: " + (s.length() - s.toLowerCase().replaceAll("a|e|i|o|u|", "").length()));
//Also eliminating spaces, if any for the consonant count
System.out.println("Consonant Count: " + (s.toLowerCase().replaceAll("a|e|i|o| |u", "").length()));
}
My code without scanner and maybe not very simple, but:
public class Main{
public static void main(String[] args) {
String test = "qwertyYVTA";
test = test.trim();
int vowels = 0;
int consonants = 0;
Pattern patternVow = Pattern.compile("[eyuioa]", Pattern.CASE_INSENSITIVE | Pattern.UNICODE_CASE);
Matcher matcherVow = patternVow.matcher(test);
while (matcherVow.find()) {
vowels++;
}
Pattern patternCons = Pattern.compile("[wrtpsdfghjklzxcvbnm]", Pattern.CASE_INSENSITIVE | Pattern.UNICODE_CASE);
Matcher matcherCons = patternCons.matcher(test);
while (matcherCons.find()) {
consonants++;
}
System.out.println("Vowels in test String is " + vowels);
System.out.println("Consonants in test String is " + consonants);
}
}