How to print 2D array to console in C#

Question

I dont\'t have any code for this, but I do want to know how I could do this. I use visual studio 2010 C# if that matters.

Thanks

Jason

Answer 1

Below is multiple solution to how to implement multidimentional array, I think it is pretty straight forward in c#.

using System;
using System.Collections.Generic;

namespace DataStructure
{
    class Program : SortedZeros
    {
        static void Main(string[] args)
        {
            // Two-Dimensional Array
            int[,] numbers2D = new int[3, 2] 
            { 
                { 9, 99 }, 
                { 3, 33 }, 
                { 5, 55 }
            };

            // 3 * 3
            int[,] dataTest2D = new int[3, 3] 
            { 
                {3, 5, 7}, 
                {4, 3, 8},
                {9, 6, 9},
            };

            // A similar array with string elements.
            int[,] matrix = new int[4, 4]
            {
                 {1, 2, 3, 6},
                 {4, 5, 6, 4},
                 {7, 8, 9, 6},
                 {7, 8, 9, 2},
            };

            int rowLength = matrix.GetLength(0);
            int colLength = matrix.GetLength(0);

            for (int i = 0; i < rowLength; i++)
            {
                for (int j = 0; j < colLength; j++)
                {
                    Console.Write(string.Format("{0} ", matrix[i, j]));
                }
                Console.Write(Environment.NewLine + Environment.NewLine);
            }

            // using foreach to print out the 2 * 2 in one straightline
            foreach (int i in numbers2D)
            {
                Console.Write("{0} ", i);
            }
            Console.WriteLine();

            Console.WriteLine();
            for (int i = 0; i < dataTest2D.GetLength(0); i++)
            {
                for (int j = 0; j < dataTest2D.GetLength(1); j++)
                {
                    Console.Write(string.Format("{0} ", dataTest2D[i, j]));
                }
                Console.Write(Environment.NewLine + Environment.NewLine);
            }
        }

    }
}

Answer 2

int[,] matrix = new int[2, 2] { {2, 2}, {1, 1} };

for (int i = 0; i < matrix.GetLength(0); i++)
{
    for (int k = 0; k < matrix.GetLength(1); k++ )
    {
        //put a single value
        Console.Write(matrix[i,k]);
    }
    //next row
    Console.WriteLine();
}

Answer 3

Try like this..

        int[,] matrix = new int[3, 3]
        {
            {1, 2, 3},
            {4, 5, 6},
            {7, 8, 9},
        };

        int rowLength = matrix.GetLength(0);
        int colLength = matrix.GetLength(1);

        for (int i = 0; i < rowLength; i++)
        {
            for (int j = 0; j < colLength; j++)
            {
                Console.Write(string.Format("{0} ", matrix[i, j]));
            }
            Console.Write(Environment.NewLine + Environment.NewLine);
        }


        Console.Read();

Answer 4

You should read MSDN:Using foreach with Arrays

int[,] numbers2D = new int[3, 2] { { 9, 99 }, { 3, 33 }, { 5, 55 } };
// Or use the short form:
// int[,] numbers2D = { { 9, 99 }, { 3, 33 }, { 5, 55 } };

foreach (int i in numbers2D)
{
    System.Console.Write("{0} ", i);
}

// Output: 9 99 3 33 5 55