Best method to round up to the nearest 0.05 in java

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太阳男子
太阳男子 2020-12-06 19:42

Consider that a tax of 10% is applicable on all items except food. Also, an additional tax of of 5 % is applicable on imported items.

If the cost of a music CD is

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  • 2020-12-06 19:57

    This seems to be part of a famous tech interview problem The point is to understand that you have to calculate the taxes and round that amount to the upper 0.05 to calculate the rounding i used this groovy script

    import java.math.*
    
    def myRound(BigDecimal d){ 
        def scale = new BigDecimal("0.05")
        def y = d.divide(scale)
        println "y :$y"
    //    def q = y.round(new MathContext(0,RoundingMode.UP))
        def q = y.setScale(0,BigDecimal.ROUND_UP)
        println "q :$q (intero)"
        def z = q.multiply(scale)
        println "z :$z"
        return z
    }
    
    def taxBy(BigDecimal d,BigDecimal t){ 
        return myRound(d.multiply(t))
    }
    def importTax(BigDecimal d){ 
        return taxBy(d,new BigDecimal("0.15"))
    }
    
    def importBaseTax(BigDecimal b){ 
        return taxBy(d,new BigDecimal("0.05"))
    }
    
    ip = new BigDecimal("27.99")
    ipt = importTax(ip)
    
    println "${ip}-->${ipt} = ${ip+ipt}"
    

    I hope this to be useful!

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  • 2020-12-06 20:10

    Store monetary amounts as integers (e.g. a number of cents).

    This is a common issue - google will give you plenty of great explanations.

    Here is one: Why not use Double or Float to represent currency?

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  • 2020-12-06 20:15

    You can use long instead of double to use double you can do

    double d = Math.round(d * 20) / 20.0; // round up to multiple of 0.05
    

    to use long (as cents)

    long l = (l + 3) / 5 * 5;
    

    Although its often considered best practice to use int, long or BigDecimal most investment banks and funds use double because once you understand how to use them safely, they are simpler (than long) and faster (than BigDecimal) to use.

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