I am trying to select the first visible cell directly beneath the header of a filtered column. The code I am getting is as below, but I have to problems with this code. Fi
Something like this might work...
Sub Macro16()
Dim ARow As Long, JRow As Long, ws1 As Worksheet
ws1 = Sheets("NAME OF SHEET WITH DATA")
ARow = ws1.Range("A" & ws1.Rows.Count).End(xlUp).Row + 1
ws1.Range("$A$1:$R$" & ARow).AutoFilter Field:=12, Criteria1:="Sheets"
JRow = ws1.Range("J" & ws1.Rows.Count).End(xlUp).Row + 1
ws1.Range("J" & JRow).FormulaR1C1 = "=RIGHT(RC[1],3)"
ws1.Range("J" & JRow).FillDown
End Sub
I prefer non-destructive methods of determining whether there are visible cells to work with after a filtering operation. Since you are filling in column J with a formula, there is no guarantee that column J contains any values tat can be counted with the worksheet's SUBTOTAL function (SUBTOTAL does not count rows hidden by a filter) but the formula you are planning to populate into column J references column K so there must be something there.
Sub Macro16()
With ActiveSheet
If .AutoFilterMode Then .AutoFilterMode = False
With .Cells(1, 1).CurrentRegion
.Columns(12).AutoFilter Field:=1, Criteria1:="Sheets"
With .Resize(.Rows.Count - 1, 1).Offset(1, 9)
If CBool(Application.Subtotal(103, .Offset(0, 1))) Then
.SpecialCells(xlCellTypeVisible).FormulaR1C1 = "=RIGHT(RC[1],3)"
End If
End With
.Columns(12).AutoFilter Field:=1
End With
End With
End Sub
Untested but:
Sub Macro16()
With ActiveSheet.Range("A1").CurrentRegion
.AutoFilter field:=12, Criteria1:="Sheets"
If .Columns(1).SpecialCells(xlCellTypeVisible).count > 1 Then
With .Columns(10)
.Resize(.rows.count - 1).offset(1).SpecialCells(xlCellTypeVisible).FormulaR1C1 = "=RIGHT(RC[1],3)"
End With
End If
End With
End Sub
Sub FirstVisibleCell()
With Worksheets("You Sheet Name").AutoFilter.Range
Range("A" & .Offset(1, 0).SpecialCells(xlCellTypeVisible)(1).Row).Select
End With
End Sub