Convert 12hour time to 24Hour time

Question

I have hourly weather data. I\'ve seen the function examples from here: http://casoilresource.lawr.ucdavis.edu/drupal/node/991

I\'m altering the code to account for

Answer 1

Would strptime work?

df2= structure(c("10:43 AM", "10:54 AM", "11:54 AM", "12:07 PM", "12:15 PM", 
            "12:54 PM", "1:54 PM", "2:54 PM"), .Dim = c(8L, 1L))



 strptime(df2, "%I:%M %p" )

Or in case you don't want the date, something like: Although it depends what kind of class would you want for the object.

substr(strptime(df2, "%I:%M %p" ),11,19)

Answer 2

take a look at ?strptime.

as.POSIXct(data$TimeEST, format='%I:%M %p')