in r combine a list of lists into one list

Question

I cannot find out can to get a list of all entry of the sublists? Here\'s a simple example, a list o lists:

listoflists <- list(\"A\"=list(c(1,2,3),c(2,34         


        

Answer 1

For your specific example, which does not have much nesting, you can also just use flatten from the "purrr" package.

library(purrr)
flatten(listoflists)

However, you don't specify the behavior you'd expect for more deeply nested lists. If you want to fully flatten a more deeply nested list, you can look at the LinearizeNestedList function by Akhil S Bhel.

Example:

LL <- list(listoflists, listoflists)
str(flatten(LL))  ## Same as `do.call(c, LL)`
# List of 6
#  $ A:List of 2
#   ..$ : num [1:3] 1 2 3
#   ..$ : num [1:3] 2 34 2
#  $ B:List of 2
#   ..$ : num [1:2] 1 2
#   ..$ : num [1:4] 2 3 2 1
#  $ C:List of 1
#   ..$ : chr [1:3] "sdf" "3" "2"
#  $ A:List of 2
#   ..$ : num [1:3] 1 2 3
#   ..$ : num [1:3] 2 34 2
#  $ B:List of 2
#   ..$ : num [1:2] 1 2
#   ..$ : num [1:4] 2 3 2 1
#  $ C:List of 1
#   ..$ : chr [1:3] "sdf" "3" "2"
str(LinearizeNestedList(LL))
# List of 10
#  $ 1/A/1: num [1:3] 1 2 3
#  $ 1/A/2: num [1:3] 2 34 2
#  $ 1/B/1: num [1:2] 1 2
#  $ 1/B/2: num [1:4] 2 3 2 1
#  $ 1/C/1: chr [1:3] "sdf" "3" "2"
#  $ 2/A/1: num [1:3] 1 2 3
#  $ 2/A/2: num [1:3] 2 34 2
#  $ 2/B/1: num [1:2] 1 2
#  $ 2/B/2: num [1:4] 2 3 2 1
#  $ 2/C/1: chr [1:3] "sdf" "3" "2"

Answer 2

We can use the concatenate function (c) within do.call to flatten the nested list

res <- do.call(c, listoflists)
all.equal(listofvectors, res, check.attributes = FALSE)
#[1] TRUE

Or as @d.b mentioned in the comments, unlist with recursive = FALSE can also work

unlist(listoflists, recursive = FALSE)