multiple routes in single Route::get() call Laravel 4

Question

When defining a route in Laravel 4 is it possible to define multiple URI paths within the same route?

presently i do the following:

Route::get(\'/\'         


        

Answer 1

If I understand your question right I'd say:

Use Route Prefixing: http://laravel.com/docs/routing#route-prefixing

Or (Optional) Route Parameters: http://laravel.com/docs/routing#route-parameters

So for example:

Route::group(array('prefix' => '/'), function() { Route::get('dashboard', 'DashboardController@index'); });

OR

Route::get('/{dashboard?}', array('as' => 'dashboard', 'uses' => 'DashboardController@index'));

Answer 2

I find it interesting for curiosity sake to attempt to solve this question posted by @Alex as a comment under @graemec's answer to post a solution that works:

Route::get('/{name}', [
    'as' => 'dashboard', 
    'uses' => 'DashboardController@index'
  ]
)->where('name', 'home|dashboard|'); //add as many as possible separated by |

Because the second argument of where() expects regular expressions so we can assign it to match exactly any of those separated by | so my initial thought of proposing a whereIn() into Laravel route is resolved by this solution.

PS:This example is tested on Laravel 5.4.30

Hope someone finds it useful

Answer 3

I believe you need to use an optional parameter with a regular expression:

Route::get('/{name}', array(
     'as' => 'dashboard', 
     'uses' => 'DashboardController@index')
    )->where('name', '(dashboard)?');

* Assuming you want to route to the same controller which is not entirely clear from the question.

* The current accepted answer matches everything not just / OR /dashboard.