This code works and prints \"b\":
fn main() {
let s = \"abc\";
let ch = s.chars().nth(1).unwrap();
println!(\"{}\", ch);
}
On t
The as operator works for all number types:
let ch = s.chars().nth(n as usize).unwrap();
Rust forces you to cast integers to make sure you're aware of signedness or overflows.
Integer constants can have a type suffix:
let n = 1u32;
However, note that negative constants, such as -1i32 is internally - 1i32.
Integer variables declared without an explicit type specification are shown as {integer} and will be properly inferred from one of the method calls.
The most cautious thing you can do is to use TryFrom and panic when the value cannot fit within a usize:
use std::convert::TryFrom;
fn main() {
let s = "abc";
let n: u32 = 1;
let n_us = usize::try_from(n).unwrap();
let ch = s.chars().nth(n_us).unwrap();
println!("{}", ch);
}
By blindly using as, your code will fail in mysterious ways when run on a platform where usize is smaller than 32-bits. For example, some microcontrollers use 16-bit integers as the native size:
fn main() {
let n: u32 = 0x1_FF_FF;
// Pretend that `usize` is 16-bit
let n_us: u16 = n as u16;
println!("{}, {}", n, n_us); // 131071, 65535
}
We now have a pretty different answer when we try to compile your code, replacing the number 1 with a variable of type i32:
error[E0308]: mismatched types
--> src/main.rs:5:28
|
5 | let ch = s.chars().nth(n).unwrap();
| ^ expected usize, found i32
help: you can convert an `i32` to `usize` and panic if the converted value wouldn't fit
|
5 | let ch = s.chars().nth(n.try_into().unwrap()).unwrap();
|
It means that now the compiler recommends you to use n.try_into().unwrap() that makes use of the trait TryInto which in turn relies on TryFrom and returns a Result<T, T::Error>. That's why we need to extract the result with a .unwrap()
TryInto documentation