jQgrid posting custom data on load

Question

Wondering if anyone has used jQgrid to post dynamic data from another form on the same page. Dynamic in that I don\'t know the input names to post, but would rather just po

Answer 1

I am not sure in which form you want to get the data from the form on the server side. Nevertheless I would suggest you to use postData in the following form

postData: {
    filter: function () {
        var result = {}, i, item,
            formInfo = $('form#myForm').serializeArray(),
            l = formInfo.length;
        for (i = 0; i < l; i++) {
            item = formInfo[i];
            result[item.name] = item.value;
        }

        return JSON.stringify(result);
    }
}

In case of the following test form

<form id="myForm">
  <div><input type="text" name="a" value="1 from a" id="a" /></div>
  <div><input type="text" name="b" value="2 from b" id="b" /></div>
  <div><input type="hidden" name="c" value="3 from c" id="c" /></div>
  <div>
    <textarea name="d" rows="8" cols="40">4</textarea>
  </div>
  <div><select name="e">
    <option value="5" selected="selected">5</option>
    <option value="6">6</option>
    <option value="7">7</option>
  </select></div>
  <div>
    <input type="checkbox" name="f" value="8" id="f" />
  </div>
</form>

The result variable will be

var result = {
    a: "1 from a",
    b: "2 from b",
    c: "3 from c",
    d: "4",
    e: "5"
}

So no conversion of the data will be done. Then I suggest to convert object result to JSON string using JSON.stringify. (Depend on the server code it could be not needed.) So the filters parameter will be sent as

{"a":"1 from a","b":"2 from b","c":"3 from c","d":"4","e":"5"}

You can use Fiddler or Firebug to examine the HTTP traffic of the corresponding small demo.