How to output float to cout without scientific notation or trailing zeros?

Question

What is the most elegant way to output a floating point number in C++ with no scientific notation or trailing zeros?

Answer 1

If string manipulating doesn't hurt your eyes:

std::string fixedfloat(float x)
{
    std::ostringstream ss;
    ss << std::fixed << std::setprecision(std::cout.precision()) << x;
    std::string str = ss.str();
    return str.substr(0, str.find_last_not_of('0') + 1);
}

int main()
{
    float b = 0.1f;

    std::cout << std::setprecision(6) << fixedfloat(b);
}

or

class fixedfloat
{
public:
    fixedfloat(float x) : x(x) {}
    float value() const { return x; }

private:
    float x;
};

ostream &operator<<(ostream &out, const fixedfloat &f)
{
    ostringstream ss;
    ss << fixed << setprecision(out.precision()) << f.value();
    string str = ss.str();
    out << str.substr(0, str.find_last_not_of('0') + 1);
    return out;
}

int main()
{
    float b = 0.1f;

    cout << setprecision(6) << fixedfloat(b);
}

Answer 2

I am not sure about the "most elegant way" but here's one way.

#include <iostream>
#include <iomanip>
#include <sstream>

using namespace std ;
string fix( float x, int p )
{
    ostringstream strout ;
    strout << fixed << setprecision(p) << x ;
    string str = strout.str() ;
    size_t end = str.find_last_not_of( '0' ) + 1 ;
    return str.erase( end ) ;
}


int main()
{
    float a = 0.000001f ;
    float b = 0.1f ;

    cout << "a: " << fix( a, 6 ) << endl;     //  0.000001 ok.
    cout << "b: " << fix( b, 6 ) << endl;     //  0.1 ok.

   return 0;
}

You could perhaps create your own I/O manipulator if you need to to a lot of this kind of output. That is arguably more elegant, but the implementation could be similar.

Answer 3

the other example like mine actually output "200." or did "200" >> "2".

this should work for everything (as I took it from a string to val function I use).

string fix(float in) {       
    string s = to_string(in);
    size_t dot = s.find_first_of('.'), last = s.find_last_not_of(".0");

    if (dot!=string::npos) return s.substr(0, max(dot,last+1));
    else return s;
}