How can i convert a narrow string
to a wide string
?
I have tried this method :
string myName;
getline( cin , myName );
wst
You should do this :
inline std::wstring convert( const std::string& as )
{
// deal with trivial case of empty string
if( as.empty() ) return std::wstring();
// determine required length of new string
size_t reqLength = ::MultiByteToWideChar( CP_UTF8, 0, as.c_str(), (int)as.length(), 0, 0 );
// construct new string of required length
std::wstring ret( reqLength, L'\0' );
// convert old string to new string
::MultiByteToWideChar( CP_UTF8, 0, as.c_str(), (int)as.length(), &ret[0], (int)ret.length() );
// return new string ( compiler should optimize this away )
return ret;
}
This expects the std::string to be UTF-8 (CP_UTF8
), when you have another encoding replace the codepage.
Another way could be :
inline std::wstring convert( const std::string& as )
{
wchar_t* buf = new wchar_t[as.size() * 2 + 2];
swprintf( buf, L"%S", as.c_str() );
std::wstring rval = buf;
delete[] buf;
return rval;
}
This article published on the MSDN Magazine 2016 September issue discusses the conversion in details using Win32 APIs.
Note that using MultiByteToWideChar()
is much faster than using the std:: stuff on Windows.
Here are two functions that can be used: mbstowcs_s and wcstombs_s.
mbstowcs_s: Converts a sequence of multibyte characters to a corresponding sequence of wide characters. wcstombs_s: Converts a sequence of wide characters to a corresponding sequence of multibyte characters.
errno_t wcstombs_s(
size_t *pReturnValue,
char *mbstr,
size_t sizeInBytes,
const wchar_t *wcstr,
size_t count
);
errno_t mbstowcs_s(
size_t *pReturnValue,
wchar_t *wcstr,
size_t sizeInWords,
const char *mbstr,
size_t count
);
See http://msdn.microsoft.com/en-us/library/eyktyxsx.aspx and http://msdn.microsoft.com/en-us/library/s7wzt4be.aspx.
Use mbtowc():
string myName;
wchar_t wstr[BUFFER_SIZE];
getline( cin , myName );
mbtowc(wstr, myName, BUFFER_SIZE);
If the source is ASCII encoded, you can just do this:
wstring printerName;
printerName.assign( myName.begin(), myName.end() );
I found this while googling the problem. I have pasted the code for reference. Author of this post is Paul McKenzie.
std::string str = "Hello";
std::wstring str2(str.length(), L' '); // Make room for characters
// Copy string to wstring.
std::copy(str.begin(), str.end(), str2.begin());