remove last few characters in PySpark dataframe column

Question

I am having a PySpark DataFrame. How can I chop off/remove last 5 characters from the column name below -

from pyspark.sql.functions import subs         


        

Answer 1

You can use expr function

>>> from pyspark.sql.functions import substring, length, col, expr
>>> df = df.withColumn("flower",expr("substring(name, 1, length(name)-5)"))
>>> df.show()
+--------------+----+---------+
|          name|year|   flower|
+--------------+----+---------+
|     rose_2012|2012|     rose|
|  jasmine_2013|2013|  jasmine|
|     lily_2014|2014|     lily|
| daffodil_2017|2017| daffodil|
|sunflower_2016|2016|sunflower|
+--------------+----+---------+

Answer 2

In this case, since we want to extract alphabetical characters, so REGEX will also work.

from pyspark.sql.functions import regexp_extract 
df = df.withColumn("flower",regexp_extract(df['name'], '[a-zA-Z]+',0))
df.show()
+--------------+----+---------+
|          name|year|   flower|
+--------------+----+---------+
|     rose_2012|2012|     rose|
|  jasmine_2013|2013|  jasmine|
|     lily_2014|2014|     lily|
| daffodil_2017|2017| daffodil|
|sunflower_2016|2016|sunflower|
+--------------+----+---------+

Answer 3

You can use split function. this code does what you want:

import pyspark.sql.functions as f

newDF = df.withColumn("year", f.split(df['name'], '\_')[1]).\
           withColumn("flower", f.split(df['name'], '\_')[0])

newDF.show()

+--------------+----+---------+
|          name|year|   flower|
+--------------+----+---------+
|     rose_2012|2012|     rose|
|  jasmine_2013|2013|  jasmine|
|     lily_2014|2014|     lily|
| daffodil_2017|2017| daffodil|
|sunflower_2016|2016|sunflower|
+--------------+----+---------+

Answer 4

Adding little tweak to avoid hard coding and identify column length dynamically through location of underscore('_') using instr function.

df = spark.createDataFrame([('rose_2012',),('jasmine_2013',),('lily_2014',),('daffodil_2017',),('sunflower_2016',)],['name'])


df.withColumn("flower",expr("substr(name, 1, (instr(name,'_')-1) )")).\
        withColumn("year",expr("substr(name, (instr(name,'_')+1),length(name))")).show()