Comparing phone numbers in Android

Question

I need to compare two phone numbers to determine if they\'re from the same sender/receiver. The user may send a message to a contact, and that contact may reply.

The

Answer 1

just apply your logic to remove () and - and follow PhoneNumberUtils

Answer 2

How about checking if the number is a substring of the receiver's number?

For instance, let's say my Brazilian number is 888-777-666 and yours is 111-222-333. To call you, from here, I need to dial additional numbers to make international calls. Let's say I need to add 9999 + your_number, resulting in 9999111222333.

If RawNumber.substring(your_number) returns true I can say that I'm calling you.

Answer 3

Android has nice PhoneNumberUtils, and i guess your looking for :

    public static boolean compare (String a, String b)

look in : http://developer.android.com/reference/android/telephony/PhoneNumberUtils.html

using it should look like this :

String phone1   
String phone2 

 if (PhoneNumberUtils.compare(phone1, phone2)) {
    //they are the same do whatever you want!
   }

Answer 4

android.telephony.PhoneNumberUtils class provides almost all necessary functions to deal with phone numbers and standards.

For your case, the solution is PhoneNumberUtils.compare(Context context, String number1, String number2) or else PhoneNumberUtils.compare(String number1, String number2).The former one checks a resource to determine whether to use a strict or loose comparison algorithm, thus the better choice in most cases.

PhoneNumberUtils.compare("0712593276", "+94712593276") // always true
PhoneNumberUtils.compare("0712593276", "+44712593276") // always true

// true or false depends on the context
PhoneNumberUtils.compare(context, "0712593276", "+94712593276") 

Take a look at the official documentation. And the source code.