Are arithmetic operations on literals calculated at compile time or run time?

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挽巷
挽巷 2020-12-06 09:14

I have the following:

double timeInMinutes = (double) timeInMilliseconds / (1000 * 60);

Is the operation (1000 * 60) done at c

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  • 2020-12-06 09:37

    As per JLS §15.2 - Forms of Expressions

    Some expressions have a value that can be determined at compile time. These are constant expressions (§15.28).

    Multiplicative operators like *, /, and % falls under constant expressions, so it would be determined at compile time.

    @SergeyMorozov was faster than me to write and get byte code proof (#2 = Integer 60000) but here is the practical proof and above is theoretical/official statement:

    Try generating byte code at your end as well using 1000 * 60 and 60000, and you will see same byte code instructions, and hence there would be same runtime performance.

    Java class:

    public class Test {
        public static void main(String[] args) {
            int compileTest = 1000 * 60;
        }
    }
    

    Byte code:

    Classfile /E:/Test.class
      Last modified Oct 9, 2015; size 265 bytes
      MD5 checksum fd115be769ec6ef7995e4c84f7597d67
      Compiled from "Test.java"
    public class Test
      SourceFile: "Test.java"
      minor version: 0
      major version: 51
      flags: ACC_PUBLIC, ACC_SUPER
    Constant pool:
       #1 = Methodref          #4.#13         //  java/lang/Object."<init>":()V
       #2 = Integer            60000
       #3 = Class              #14            //  Test
       #4 = Class              #15            //  java/lang/Object
       #5 = Utf8               <init>
       #6 = Utf8               ()V
       #7 = Utf8               Code
       #8 = Utf8               LineNumberTable
       #9 = Utf8               main
      #10 = Utf8               ([Ljava/lang/String;)V
      #11 = Utf8               SourceFile
      #12 = Utf8               Test.java
      #13 = NameAndType        #5:#6          //  "<init>":()V
      #14 = Utf8               Test
      #15 = Utf8               java/lang/Object
    {
      public Test();
        flags: ACC_PUBLIC
        Code:
          stack=1, locals=1, args_size=1
             0: aload_0
             1: invokespecial #1                  // Method java/lang/Object."<init>":()V
             4: return
          LineNumberTable:
            line 1: 0
    
      public static void main(java.lang.String[]);
        flags: ACC_PUBLIC, ACC_STATIC
        Code:
          stack=1, locals=2, args_size=1
             0: ldc           #2                  // int 60000
             2: istore_1
             3: return
          LineNumberTable:
            line 3: 0
            line 4: 3
    }
    
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  • 2020-12-06 09:42

    At compile time. This is one of those most basic compiler optimizations, known as Constant Folding.

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  • 2020-12-06 09:47

    Just create class Test

    public class Test {
        public static void main(String [] args) {
            long timeInMilliseconds = System.currentTimeMillis();
            double timeInMinutes = (double) timeInMilliseconds / (1000 * 60);
            System.out.println(timeInMinutes);
        }
    }
    

    and decompile it using command: javap -v Test

    You can see output of decompiled class:

      public static void main(java.lang.String[]);
    flags: ACC_PUBLIC, ACC_STATIC
    Code:
      stack=4, locals=5, args_size=1
         0: invokestatic  #2                  // Method java/lang/System.currentTimeMillis:()J
         3: lstore_1
         4: lload_1
         5: l2d
         6: ldc2_w        #3                  // double 60000.0d
         9: ddiv
        10: dstore_3
        11: getstatic     #5                  // Field java/lang/System.out:Ljava/io/PrintStream;
        14: dload_3
        15: invokevirtual #6                  // Method java/io/PrintStream.println:(D)V
        18: return
      LineNumberTable:
        line 3: 0
        line 4: 4
        line 5: 11
        line 6: 18
    

    Take a look on the line 6: ldc2_w #3 // double 60000.0d

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