How to bind socket to an interface in python (socket.SO_BINDTODEVICE missing)

Question

This is probably a very simple thing. I\'m new to python so don\'t crucify me.

s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.setsockopt(socket.SOL_         


        

Answer 1

In Python, SO_BINDTODEVICE is present in IN module. Importing IN will solve the problem.

import socket
import IN

sock = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
sock.setsockopt(socket.SOL_SOCKET, IN.SO_BINDTODEVICE, "eth0")

Answer 2

If you don't understand the error message, it means you're referring a name IN which is not available at that point. Your code snippet is likely missing an import statement.

The socket module may not offer SO_BINDTODEVICE for portability reasons. If you are absolutely sure that you're running on Linux that supports it, try replacing it with it's numerical value, which is 25:

s.setsockopt(socket.SOL_SOCKET, 25, "eth1"+'\0')

Or for python 3:

s.setsockopt(socket.SOL_SOCKET, 25, str("eth1" + '\0').encode('utf-8'))

Answer 3

Beware: SO_BINDTODEVICE won't work with packet sockets - Linux man-page man 7 socket

It is not supported for packet sockets (use normal bind(2) there).

Python-Example for eth1 with bind():

rawSocket = socket.socket(socket.AF_PACKET, socket.SOCK_RAW, socket.htons(3))
rawSocket.bind(('eth1',0))

Answer 4

You may even "export" a missing option:

if not hasattr(socket,'SO_BINDTODEVICE') :
    socket.SO_BINDTODEVICE = 25

then

sock.setsockopt(socket.SOL_SOCKET, socket.SO_BINDTODEVICE, interface+'\0')