Sort upcoming birthdays based on current date

Question

I have the following table of people and their birthdays:

name        birthday
----------------------
yannis      1979-06-29
natalia     1980-08-19
kostas            


        

Answer 1

Here is one way:

• Calculate current year - year of birth
• Add the resulting number of years to the date of birth
• You now have the birthday this year, if this date has passed then add one more year
• Sort the results by that date

SELECT
    name,
    birthday,
    birthday + INTERVAL (YEAR(CURRENT_DATE) - YEAR(birthday))     YEAR AS currbirthday,
    birthday + INTERVAL (YEAR(CURRENT_DATE) - YEAR(birthday)) + 1 YEAR AS nextbirthday
FROM birthdays
ORDER BY CASE
    WHEN currbirthday >= CURRENT_DATE THEN currbirthday
    ELSE nextbirthday
END

Notes:

• Today's birthdays appears first regardless of current time
• February 29 birthday is treated equal to February 28 birthday for common years e.g.
  • On Jan/1/2019 both Feb 28 and Feb 29 birthdays (2019) are sorted equal
  • On Mar/1/2019 Feb 28 and Feb 29 birthdays (2020) are sorted as expected

SQLFiddle

Answer 2

Not pretty, but works

SELECT * 
,CASE WHEN BirthdayThisYear>=NOW() THEN BirthdayThisYear ELSE BirthdayThisYear + INTERVAL 1 YEAR END AS NextBirthday
FROM (
    SELECT * 
    ,birthday - INTERVAL YEAR(birthday) YEAR + INTERVAL YEAR(NOW()) YEAR AS BirthdayThisYear
    FROM bd
) AS bdv
ORDER BY NextBirthday

Answer 3

Seems to be rather fast, no problems with leap years:

SELECT * 
FROM `people` 
ORDER BY CONCAT(SUBSTR(`birthday`,6) < SUBSTR(CURDATE(),6), SUBSTR(`birthday`,6))

Все гениальное -- просто! ;)

Answer 4

SELECT name
     , birthday
FROM TableX
ORDER BY DAYOFYEAR(birthday) < DAYOFYEAR(CURDATE())
       , DAYOFYEAR(birthday)

---

No, the above may produce error results, due to years with 366 days. This is correct:

SELECT name
     , birthday
FROM
  ( SELECT name
         , birthday
         , MONTH(birthday) AS m
         , DAY(birthday) As d
    FROM TableX
  ) AS tmp
ORDER BY (m,d) < ( MONTH(CURDATE()), DAY(CURDATE()) )
       , m
       , d

---

If your table grows to more than a few thousands records, it will be real slow. If you want a fast query, add fields with the month and day and have an index on (bmonth,bday) or add them as one field, either Char (08-17 or 0817 for 17-Aug) or Int (817 for 17-Aug) and an index on that field.

Answer 5

i would try it like this (but this isn't tested):

SELECT
  name,
  birthday
FROM
  birthdays
ORDER BY
  ABS( DAYOFYEAR(birthday) - (DAYOFYEAR(CURDATE()) ) ASC

EDIT:
changed ordering from DESC to ASC because you want to get the farthest first, not the closest.