I have a simple problem, but can\'t come with a simple solution :)
Let\'s say I have a string. I want to detect if there is a repetition in it.
I\'d like:
import re
def repetitions(s):
r = re.compile(r"(.+?)\1+")
for match in r.finditer(s):
yield (match.group(1), len(match.group(0))/len(match.group(1)))
finds all non-overlapping repeating matches, using the shortest possible unit of repetition:
>>> list(repetitions("blablabla"))
[('bla', 3)]
>>> list(repetitions("rablabla"))
[('abl', 2)]
>>> list(repetitions("aaaaa"))
[('a', 5)]
>>> list(repetitions("aaaaablablabla"))
[('a', 5), ('bla', 3)]