Python: how to build a dict from plain list of keys and values

Question

I have a list of values like:

[\"a\", 1, \"b\", 2, \"c\", 3]

and I would like to build such a dict from it:

{\"a\": 1, \"b\         


        

Answer 1

I don't really see many situations where you would run into this exact problem, so there is no 'natural' solution. A quick one liner that should do the trick for you would be however:

   {input_list[2*i]:input_list[2*i+1] for i in range(len(input_list)//2)}

Answer 2

>>> x = ["a", 1, "b", 2, "c", 3]
>>> i = iter(x)
>>> dict(zip(i, i))
{'a': 1, 'c': 3, 'b': 2}

Answer 3

You can zip the lists of alternate elements like so

>>> lst = ["a", 1, "b", 2, "c", 3]
>>> dict(zip(lst[::2], lst[1::2])
{'a': 1, 'c': 3, 'b': 2}

Answer 4

This seems rather succint, but I wouldn't call it very natural:

>>> l = ["a", 1, "b", 2, "c", 3]
>>> dict(zip(l[::2], l[1::2]))
{'a': 1, 'c': 3, 'b': 2}

Answer 5

Another way:

>>> l = ["a", 1, "b", 2, "c", 3]
>>> dict([l[i:i+2] for i in range(0,len(l),2)])
{'a': 1, 'c': 3, 'b': 2}