Python summing up time

Question

In python how do I sum up the following time?

 0:00:00
 0:00:15
 9:30:56

Answer 1

lines = ["0:00:00", "0:00:15", "9:30:56"]
total = 0
for line in lines:
    h, m, s = map(int, line.split(":"))
    total += 3600*h + 60*m + s
print "%02d:%02d:%02d" % (total / 3600, total / 60 % 60, total % 60)

Answer 2

from datetime import timedelta

h = ['3:00:00','1:07:00', '4:00:00', '4:05:00', '4:10:00', '4:03:00']

def to_td(h):
    ho, mi, se = h.split(':')
    return timedelta(hours=int(ho), minutes=int(mi), seconds=int(se))

print(str(sum(map(to_td, h), timedelta())))

# Out[31]: 20:25:00

Answer 3

Naive approach (without exception handling):

#!/usr/bin/env python

def sumup(*times):
    cumulative = 0
    for t in times:
        hours, minutes, seconds = t.split(":")
        cumulative += 3600 * int(hours) + 60 * int(minutes) + int(seconds)
    return cumulative

def hms(seconds):
    """Turn seconds into hh:mm:ss"""
    hours = seconds / 3600
    seconds -= 3600*hours
    minutes = seconds / 60
    seconds -= 60*minutes
    return "%02d:%02d:%02d" % (hours, minutes, seconds)

if __name__ == '__main__':
    print hms(sumup(*("0:00:00", "0:00:15", "9:30:56")))
    # will print: 09:31:11