Open image in Windows Photo Viewer

Question

How to open .jpg image in Windows Photo Viewer from C# app?

Not inside app like this code,

FileStream stream = new FileStream(\"test.p         


        

Answer 1

The code fetch photo from ftp and shows the photo in Windows Photo Viewer. I hope it will usefully for you.

  public void ShowPhoto(String uri, String username, String password)
        {
            WebClient ftpClient = new WebClient();
            ftpClient.Credentials = new NetworkCredential(username,password);
            byte[] imageByte = ftpClient.DownloadData(uri);


            var tempFileName = Path.GetTempFileName();
            System.IO.File.WriteAllBytes(tempFileName, imageByte);

            string path = Environment.GetFolderPath(
                Environment.SpecialFolder.ProgramFiles);

            // create our startup process and argument
            var psi = new ProcessStartInfo(
                "rundll32.exe",
                String.Format(
                    "\"{0}{1}\", ImageView_Fullscreen {2}",
                    Environment.Is64BitOperatingSystem ?
                        path.Replace(" (x86)", "") :
                        path
                        ,
                    @"\Windows Photo Viewer\PhotoViewer.dll",
                    tempFileName)
                );

            psi.UseShellExecute = false;

            var viewer = Process.Start(psi);
            // cleanup when done...
            viewer.EnableRaisingEvents = true;
            viewer.Exited += (o, args) =>
            {
                File.Delete(tempFileName);
            };


        }

Best Regards...

Answer 2

I think you can just use:

Process.Start(@"C:\MyPicture.jpg");

And this will use the standard file viewer associated with .jpg files - by default the windows picture viewer.

Answer 3

Start it in a new Process

Process photoViewer = new Process();
photoViewer.StartInfo.FileName = @"The photo viewer file path";
photoViewer.StartInfo.Arguments = @"Your image file path";
photoViewer.Start();