How do I extract Month and Year in a MySQL date and compare them?

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天涯浪人
天涯浪人 2020-12-05 22:51

How do I extract the month and date from a mySQL date and compare it to another date?

I found this MONTH() but it only gets the month. I looking for month and year.<

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  • 2020-12-05 23:04

    If you are comparing between dates, extract the full date for comparison. If you are comparing the years and months only, use

    SELECT YEAR(date) AS 'year', MONTH(date) AS 'month'
     FROM Table Where Condition = 'Condition';
    
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  • 2020-12-05 23:15

    You may want to check out the mySQL docs in regard to the date functions. http://dev.mysql.com/doc/refman/5.5/en/date-and-time-functions.html

    There is a YEAR() function just as there is a MONTH() function. If you're doing a comparison though is there a reason to chop up the date? Are you truly interested in ignoring day based differences and if so is this how you want to do it?

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  • 2020-12-05 23:17

    in Mysql Doku: http://dev.mysql.com/doc/refman/5.5/en/date-and-time-functions.html#function_extract

    SELECT EXTRACT( YEAR_MONTH FROM `date` ) 
    FROM `Table` WHERE Condition = 'Condition';
    
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  • 2020-12-05 23:24
    SELECT * FROM Table_name Where Month(date)='10' && YEAR(date)='2016';
    
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  • 2020-12-05 23:25

    While it was discussed in the comments, there isn't an answer containing it yet, so it can be easy to miss. DATE_FORMAT works really well and is flexible to handle many different patterns.

    DATE_FORMAT(date,'%Y%m')
    

    To put it in a query:

    SELECT DATE_FORMAT(test_date,'%Y%m') AS date FROM test_table;
    
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  • 2020-12-05 23:25

    There should also be a YEAR().

    As for comparing, you could compare dates that are the first days of those years and months, or you could convert the year/month pair into a number suitable for comparison (i.e. bigger = later). (Exercise left to the reader. For hints, read about the ISO date format.)

    Or you could use multiple comparisons (i.e. years first, then months).

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