Use saxon with python

Question

I need to process XSLT using python, currently I\'m using lxml which only support XSLT 1, now I need to process XSLT 2 is there any way to use saxon XSLT processor with pyth

Answer 1

A Python interface for Saxon/C is in development and worth a look:

https://github.com/ajelenak/pysaxon

Answer 2

There are two possible approaches:

1. set up an HTTP service that accepts tranformation requests and implements them by invoking Saxon from Java; you can then send the transformation requests from Python over HTTP

2. use the Saxon/C product, currently available on prerelease: details here: http://www.saxonica.com/saxon-c/index.xml

Answer 3

If you're using Windows:

Download the zip file Saxon-HE 9.9 for Java from http://saxon.sourceforge.net/#F9.9HE and unzip the file to C:\saxon

Use this Python code:

import os
import subprocess

def file_path(relative_path):
    folder = os.path.dirname(os.path.abspath(__file__))
    path_parts = relative_path.split("/")
    new_path = os.path.join(folder, *path_parts)
    return new_path

def transform(xml_file, xsl_file, output_file):
    """all args take relative paths from Python script"""
    input = file_path(xml_file)
    output = file_path(output_file)
    xslt = file_path(xsl_file)

    subprocess.call(f"java -cp C:\saxon\saxon9he.jar net.sf.saxon.Transform -t -s:{input} -xsl:{xslt} -o:{output}")

Answer 4

Saxon/C release 1.2.0 is now out with XSLT 3.0 support for Python3 see details:

http://www.saxonica.com/saxon-c/index.xml

Answer 5

At the moment there is not, but you could use the subprocess module to use the Saxon processor:

import subprocess

subprocess.call(["saxon", "-o:output.xml", "-s:file.xml", "file.xslt"])