Android: Non-static method cannot be referenced from static context. Confused? [duplicate]

Answer 1

this worked for me ty! :)

@Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);

        TextView output1 = new TextView(this);
        output1.setText("Wow!");

        setContentView(output1);

Answer 2

Change Last Line to

output1.setText(result);

Answer 3

Try this

output1.setText(result);

You can't used setText() directly to EditText. For that you'll create a object of EditText and used setText() on it. like so

 EditText output1 = (EditText)findViewById(R.id.output);
 output1.setText(result);

Answer 4

Also, this could be due to trying to access a class' method directly rather than from instantiating it, such as:

int returnVal = SomeViewModelClass.updateRecord(table, values, where);

This will result in the error: "Non-static method cannot be referenced from static context"

So, ensure that you have instantiated it appropriately, in this case like:

private SomeViewModelClass mSomeViewModelClass;
.
.
.
mSomeViewModelClass = ViewModelProviders.of(this).get(SomeViewModelClass.class);

I've had this happen, generated the error, when I deleted the leading letter, in this case "m", from the instance name or from forgetting to instantiate. So, you might not see this immediately and bang your head on the desk for a while, which is what I just did that brought me to submit this answer!

Answer 5

In a static context, you don't have an object (instance of the class), but the instance variables and methods depend on them.

You have an instance, called output1, but you try to call your method 'setText' through the class's name (which is a static approach).

Change your lines

EditText output1 = (EditText)findViewById(R.id.output);
    EditText.setText(result);

to

EditText output1 = (EditText)findViewById(R.id.output);
    output1.setText(result);

Answer 6

Change

EditText.setText(result);

to

output1.setText(result);