How to escape the % (percent) sign in C's printf?

Question

How do you escape the % sign when using printf in C?

printf(\"hello\\%\"); /* not like this */

Answer 1

If there are no formats in the string, you can use puts (or fputs):

puts("hello%");

if there is a format in the string:

printf("%.2f%%", 53.2);

As noted in the comments, puts appends a \n to the output and fputs does not.

Answer 2

Like this:

printf("hello%%");
//-----------^^ inside printf, use two percent signs together

Answer 3

You can use %%:

printf("100%%");

The result is:

100%

Answer 4

you are using incorrect format specifier you should use %% for printing %. Your code should be:

printf("hello%%");  

Read more all format specifiers used in C.

Answer 5

Yup, use printf("hello%%"); and it's done.

Answer 6

With itself...

printf("hello%%"); /* like this */