What is the difference between 'a' and “a”?

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离开以前 2020-12-05 20:40

I am learning C++ and have got a question that I cannot find the answer to.

What is the difference between a char constant (using single quotes) and a s

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  • 2020-12-05 20:42

    Single quotes are used to surround character literals. Double quotes are used to surround string (character array) literals.

    Many interfaces, such as cout <<, accept either.

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  • 2020-12-05 20:48

    "a" is an array of characters that just happens to only contain one character, or two if you count the \0 at the end. 'a' is one character. They're not the same thing. For example:

    #include <stdio.h>
    
    void test(char c) {
        printf("Got character %c\n", c);
    }
    
    void test(const char* c) {
        printf("Got string %s\n", c);
    }
    
    int main() {
        test('c');
        test("c");
    }
    

    This will use two different overloads; see http://codepad.org/okl0UcCN for a demo.

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  • 2020-12-05 20:52

    'a' - 1) Character constant 2) size - 1 Character 3) Not a collection of Character array

    "a" -1) String literals 2) size - 2 Character 3) collection of Character array

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  • 2020-12-05 20:55

    A single quoted 'a' is a literal of type char. A double quoted "a" is a null-terminated string literal of chars.

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  • 2020-12-05 21:03
    • "a" -> it denotes it is a string. in c++ string is a collection of characters array.
    • so string is terminated by delimiter '\0' it indicates the end of string.
    • so its size would be 2 because 1-byte for "a" and 1-byte for '\0'

    where in case of 'a'-> it is single character. so its size would be 1-byte.

    char str[]="a"; 
    

    or

    char *ptr = "c";
    
    for  'c' -> char c = 'a';
    

    or we can write as well

    char c = 97;
    
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  • 2020-12-05 21:05

    'a' is a character literal. It's of type char, with the value 97 on most systems (the ASCII/Latin-1/Unicode encoding for the letter a).

    "a" is a string literal. It's of type const char[2], and refers to an array of 2 chars with values 'a' and '\0'. In most, but not all, contexts, a reference to "a" will be implicitly converted to a pointer to the first character of the string.

    Both

    cout << 'a';
    

    and

    cout << "a";
    

    happen to produce the same output, but for different reasons. The first prints a single character value. The second successively prints all the characters of the string (except for the terminating '\0') -- which happens to be the single character 'a'.

    String literals can be arbitrarily long, such as "abcdefg". Character literals almost always contain just a single character. (You can have multicharacter literals, such as 'ab', but their values are implementation-defined and they're very rarely useful.)

    (In C, which you didn't ask about, 'a' is of type int, and "a" is of type char[2] (no const)).

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