How do I convert decimal to hexadecimal in Perl?

Question

How can I convert a number, $d = 1024, in decimal to 0xFF in hex in Perl?

The d variable needs to be assigned to a different variable and b

Answer 1

I put these snippets into Perl files in my $PATH:

Convert list of decimal numbers into hexadecimal and binary

for ($i = 0; $i < @ARGV; $i++) {
    printf("%d\t= 0x%x\t= 0b%b\n", $ARGV[$i], $ARGV[$i], $ARGV[$i]);
}

Convert list of hexadecimal numbers into decimal and binary

for ($i = 0; $i < @ARGV; $i++) {
    $val = hex($ARGV[$i]);
    printf("0x%x\t= %d\t= 0b%b\n", $val, $val, $val);
}

Convert list of binary numbers into decimal and hexadecimal

for ($i = 0; $i < @ARGV; $i++) {
    # The binary numbers you type must start with '0b'
    $val = oct($ARGV[$i]);
    printf("0b%b\t= %d\t= 0x%x\n", $val, $val, $val);
}

Answer 2

1024 in decimal is not 0xFF in hex. Instead, it is 0x400.

You can use sprintf as:

my $hex = sprintf("0x%X", $d);

Answer 3

Caveat: sprintf overflows at 2⁶⁴ ≅ 10¹⁹, on 32-bit even already at only 2³² ≅ 4×10⁹.

For large numbers, enable the lexical pragma bigint. as_hex is documented in Math::BigInt.

use bigint;
my $n = 2**65;
print $n->as_hex;   # '0x20000000000000000'

Answer 4

You can use the classical printf().

printf("%x",$d);