web.xml 404 redirect to servlet, how to get the original URI?

Question

I\'m redirecting 404 errors to a servlet via the following in my web.xml.

    404
    

        

Answer 1

Yes, it's available as a request attribute with the name javax.servlet.forward.request_uri, which is keyed by RequestDispatcher#FORWARD_REQUEST_URI. The error page location is namely invoked by a simple RequestDispatcher#forward() call.

So, you can get it as follows in servlet:

String originalUri = request.getAttribute(RequestDispatcher.FORWARD_REQUEST_URI);

or in EL:

<p>Original URI: ${requestScope['javax.servlet.forward.request_uri']}</p>