Java Regexp to Match ASCII Characters

Question

What regex would match any ASCII character in java?

I\'ve already tried:

^[\\\\p{ASCII}]*$

but found that it didn\'t match lots of

Answer 1

I think question about getting ASCII characters from a raw string which has both ASCII and special characters...

public String getOnlyASCII(String raw) {
    Pattern asciiPattern = Pattern.compile("\\p{ASCII}*$");
    Matcher matcher = asciiPattern.matcher(raw);
    String asciiString = null;
    if (matcher.find()) {
        asciiString = matcher.group();
    }
    return asciiString;
}

The above program will remove the non ascii string and return the string. Thanks to @Oleg Pavliv for pattern.

For ex:

raw = ��+919986774157

asciiString = +919986774157

Answer 2

If you only want the printable ASCII characters you can use ^[ -~]*$ - i.e. all characters between space and tilde.

https://en.wikipedia.org/wiki/ASCII#ASCII_printable_code_chart

Answer 3

For JavaScript it'll be /^[\x00-\x7F]*$/.test('blah')

Answer 4

I have never used \\p{ASCII} but I have used ^[\\u0000-\\u007F]*$

Answer 5

The first try was almost correct

"^\\p{ASCII}*$"