Convert a filename to a file:// URL

Question

In WeasyPrint’s public API I accept filenames (among other types) for the HTML inputs. Any filename that works with the built-in open() should work, but I need

Answer 1

Does the following work for you?

from urlparse import urlparse, urlunparse

urlunparse(urlparse('yourURL')._replace(scheme='file'))

Answer 2

Credit to comment from @danodonovan above.

For Python3, the following code will work:

from urllib.parse import urljoin
from urllib.request import pathname2url

def path2url(path):
    return urljoin('file:', pathname2url(path))

Answer 3

For completeness, in Python 3.4+, you should do:

import pathlib

pathlib.Path(absolute_path_string).as_uri()

Answer 4

I'm not sure the docs are rigorous enough to guarantee it, but I think this works in practice:

import urlparse, urllib

def path2url(path):
    return urlparse.urljoin(
      'file:', urllib.pathname2url(path))