I\'m trying to edit my project file to enable me to have a project that builds multiple build configs at once. I\'ve done this using a batching approach and using the MSBuil
Somthing is amiss in your project file. Consider this XML:
<PropertyGroup Condition=" '$(Configuration)|$(Platform)' == '' ">
<DebugType>pdbonly</DebugType>
<Optimize>true</Optimize>
<OutputPath>C:\Folder\Etc\Output\$(Configuration)\</OutputPath>
...
</PropertyGroup>
Those properties can never be set, since even if $(Configuration) and $(Platform) are empty, they can never match the empty string when concatinated with the bar character; the minimal value for that condition is '|' and not ''. Even if corrected by making the condition compare with '|', you then go on to try to use $(Configuration) in the OutputPath in that PropertyGroup, but $(Configuration) will never have a value at the point it is used. Likewise, where you try to set $(Platform) to 'AnyCPU' it must already have that value. You probably meant to omit the condition on the first PropertyGroup altogether, and you may need to supply default values for $(Configuration) and $(Platform) in an early PropertyGroup with no conditions as well. Diff your whole project against a new project and see if there are any other oddities like this present.
Also notice that on your override of the "Build" target, you have a redundant Condition on the MSBuild task; with the same condition is on the you don't need it on any of the tasks.
I am not quite sure if I'd wanna go through such a convoluted configuration of the project's csproj file itself. I'd rather setup a separate MSBuild "BuildBoth.proj" file that has a specific target called "Both" that builds the solution in both configurations.
<Project xmlns="http://schemas.microsoft.com/developer/msbuild/2003" DefaultTargets="Both">
<!-- Calls twice for both configs -->
<Target Name="Both">
<MSBuild Projects="buildboth.sln" Targets="Rebuild" Properties="Configuration=Debug"
StopOnFirstFailure="true">
</MSBuild>
<MSBuild Projects="buildboth.sln" Targets="Rebuild" Properties="Configuration=Release"
StopOnFirstFailure="true">
</MSBuild>
</Target>
<!-- single config targets
<Target Name="Debug">
<MSBuild Projects="buildboth.sln" Targets="Rebuild" Properties="Configuration=Debug"
StopOnFirstFailure="true">
</MSBuild>
</Target>
<Target Name="Release">
<MSBuild Projects="buildboth.sln" Targets="Rebuild" Properties="Configuration=Release"
StopOnFirstFailure="true">
</MSBuild>
</Target>
-->
</Project>
Then I'd run the command (verbosity set Minimal) to target Both
C:\Projects\experiments\BuildBoth>msbuild /v:m /target:Both BuildBoth.proj
Microsoft (R) Build Engine Version 4.0.30319.1
[Microsoft .NET Framework, Version 4.0.30319.225]
Copyright (C) Microsoft Corporation 2007. All rights reserved.
BothWpf -> C:\Projects\experiments\BuildBoth\BothWpf\bin\Debug\BothWpf.exe
BothWpf -> C:\Projects\experiments\BuildBoth\BothWpf\bin\Release\BothWpf.exe
It is important to realize that when you use a "MSBuild" task, a new child MSBuild process will be started. The implication of this is that any items and properties you define in the parent MSBuild process will not be automatically passed to/visible from the child MSBuild process unless you explicitely pass them via Properties
attribute on MSBuild
element (as in <MSbuild Properties="..." />
).
To answer your question, I wrote the following self-contained example that runs a child MSBuild project for all the specified configurations:
First, create a directory for your MSBuild experiment (for example I used C:\temp\msbuildtest
)
In this directory, create the first file, main.proj
:
<Project xmlns="http://schemas.microsoft.com/developer/msbuild/2003" DefaultTargets="Build" ToolsVersion="4.0">
<ItemGroup>
<ConfigList Condition=" '@(ConfigList)' == '' and $(Config) != '' " Include="$(Config.Split('+'))" /><!-- parse all requested configurations into a list -->
<ConfigList Condition=" '@(ConfigList)' == '' " Include="Debug" /><!-- if no configurations were specified, default to Debug -->
</ItemGroup>
<!--
Build the child project for each requested configuration. -->
<Target Name="Build">
<MSBuild Projects="$(MSBuildProjectDirectory)\child.proj" Properties="Configuration=%(ConfigList.Identity);OutputPath=$(MSBuildProjectDirectory)\bin\%(ConfigList.Identity)" Targets="Build" />
</Target>
</Project>
In the same directory, create the second file, child.proj
(in your case this would be the actual C# project you're trying to build, but because I'm trying to illustrate my point, I am using a simple child project that instead of running C# compiler just prints values of properties :-) )
<Project xmlns="http://schemas.microsoft.com/developer/msbuild/2003" DefaultTargets="Build" ToolsVersion="4.0">
<Target Name="Build">
<Message Text="Building configuration $(Configuration) with output path $(OutputPath)" Importance="High" />
</Target>
</Project>
Now you can run the example. First the default, if you don't explicitly specify configurations to build:
C:\WINDOWS\Microsoft.NET\Framework\v4.0.30319\msbuild main.proj
> (cut the noise)
> Build:
> Building configuration Debug with output path C:\temp_c\d\bin\Debug
And then explicitly specified multiple configurations:
C:\WINDOWS\Microsoft.NET\Framework\v4.0.30319\msbuild main.proj /property:Config=Debug+Release+Staging+Production
> (cut the noise)
> Build:
> Building configuration Debug with output path C:\temp_c\d\bin\Debug
> Build:
> Building configuration Release with output path C:\temp_c\d\bin\Release
> Build:
> Building configuration Staging with output path C:\temp_c\d\bin\Staging
> Build:
> Building configuration Production with output path C:\temp_c\d\bin\Production
You should be able to adapt this technique to your situation.