What is the equivalent of SQL “GROUP BY HAVING” on Pandas?

Question

what would be the most efficient way to use groupby and in parallel apply a filter in pandas?

Basically I am asking for the equivalent in SQL of

sele         


        

Answer 1

As mentioned in unutbu's comment, groupby's filter is the equivalent of SQL'S HAVING:

In [11]: df = pd.DataFrame([[1, 2], [1, 3], [5, 6]], columns=['A', 'B'])

In [12]: df
Out[12]:
   A  B
0  1  2
1  1  3
2  5  6

In [13]: g = df.groupby('A')  #  GROUP BY A

In [14]: g.filter(lambda x: len(x) > 1)  #  HAVING COUNT(*) > 1
Out[14]:
   A  B
0  1  2
1  1  3

You can write more complicated functions (these are applied to each group), provided they return a plain ol' bool:

In [15]: g.filter(lambda x: x['B'].sum() == 5)
Out[15]:
   A  B
0  1  2
1  1  3

Note: potentially there is a bug where you can't write you function to act on the columns you've used to groupby... a workaround is the groupby the columns manually i.e. g = df.groupby(df['A'])).

Answer 2

I group by state and county where max is greater than 20 then subquery the resulting values for True using the dataframe loc

counties=df.groupby(['state','county'])['field1'].max()>20
counties=counties.loc[counties.values==True]