Android OpenCV Drawing Hough Lines

Question

I am trying to use OpenCV on an android phone to detect lines. I modified the \'Tutorial 1 Basic - 2. Use OpenCV Camera\' sample. I am also using Hough Line Transform as an

Answer 1

Here is my code for visual studio, hope it helps.

void drawLines(Mat &input, const std::vector<Vec2f> &lines) {
for (int i = 0; i < lines.size(); i++) {
    float alpha = CV_PI/2-atan(input.rows/input.cols);
    float r_max;
    float r_min;
    float r = lines[i][0];
    float theta = lines[i][1];
    if (theta<alpha || theta>CV_PI-alpha) {
        r_max = input.cols*cos(theta);
        r_min = input.rows*sin(theta);
        if (r > r_max) {
            Point pt1(input.cols, (r - input.cols*cos(theta)) / sin(theta));
            Point pt2((r - input.rows*sin(theta)) / cos(theta), input.rows);
            line(input, pt1, pt2, Scalar(255, 0, 0), 1);
        }
        else if (r < r_max && r > r_min) {
            Point pt1(r / cos(theta), 0);
            Point pt2((r - input.rows*sin(theta)) / cos(theta), input.rows);
            line(input, pt1, pt2, Scalar(255, 0, 0), 1);
        }
        else {
            Point pt1(r / cos(theta), 0);
            Point pt2(0, r / sin(theta));
            line(input, pt1, pt2, Scalar(255, 0, 0), 1);
        }

    }
    else {
            r_min = input.cols*cos(theta);
            r_max = input.rows*sin(theta);
            if (r > r_max) {
                Point pt1(input.cols, (r - input.cols*cos(theta)) / sin(theta));
                Point pt2((r - input.rows*sin(theta)) / cos(theta), input.rows);
                line(input, pt1, pt2, Scalar(0, 0, 255), 1);
            }
            else if (r < r_max && r > r_min) {
                Point pt1(input.cols, (r - input.cols*cos(theta)) / sin(theta));
                Point pt2(0, r / sin(theta));
                line(input, pt1, pt2, Scalar(0, 0, 255), 1);
            }
            else {
                Point pt1(r / cos(theta), 0);
                Point pt2(0, r / sin(theta));
                line(input, pt1, pt2, Scalar(0, 0, 255), 1);
            }
    }

}

Here are 2 graphs about the logic about my code I posted.

The explanation of alpha

The explanation of r_max && r_min

Answer 2

I am using HoughLineP to find lines in my frame and draw them back out.

Here is my code... hope this helps.

    Mat mYuv = new Mat();
    Mat mRgba = new Mat();
    Mat thresholdImage = new Mat(getFrameHeight() + getFrameHeight() / 2, getFrameWidth(), CvType.CV_8UC1);
    mYuv.put(0, 0, data);
    Imgproc.cvtColor(mYuv, mRgba, Imgproc.COLOR_YUV420sp2RGB, 4);
    Imgproc.cvtColor(mRgba, thresholdImage, Imgproc.COLOR_RGB2GRAY, 4);
    Imgproc.Canny(thresholdImage, thresholdImage, 80, 100, 3);
    Mat lines = new Mat();
    int threshold = 50;
    int minLineSize = 20;
    int lineGap = 20;

    Imgproc.HoughLinesP(thresholdImage, lines, 1, Math.PI/180, threshold, minLineSize, lineGap);

    for (int x = 0; x < lines.cols(); x++) 
    {
          double[] vec = lines.get(0, x);
          double x1 = vec[0], 
                 y1 = vec[1],
                 x2 = vec[2],
                 y2 = vec[3];
          Point start = new Point(x1, y1);
          Point end = new Point(x2, y2);

          Core.line(mRgba, start, end, new Scalar(255,0,0), 3);

    }

    Bitmap bmp = Bitmap.createBitmap(getFrameWidth(), getFrameHeight(), Bitmap.Config.ARGB_8888);

    if (Utils.matToBitmap(mRgba, bmp))
         return bmp;

Answer 3

You draw the lines to the mIntermediateMat image, but returning mRgba image. That's why you don't see the lines.

The -1000..1000 range for b is correct. HoughLines returns a line angle and distance from zero (a.k.a. rho and theta). To draw them, you need to convert them to two points. The 1000's are the image dimensions, if you would draw to a 2000x2000 image, increase them to 2000 or otherwise the lines will not cross the entire image.

HoughLines is different algorithm from HoughLinesP. HoughLines only finds lines, that cross the entire image. HoughLinesP returns shorter line segments.