How do I write a restful web service that accepts a binary file (pdf)

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后悔当初
后悔当初 2020-12-04 20:29

I\'m trying to write a restful web service in java that will take a few string params and a binary file (pdf) param.

I understand how to do the strings but I\'m get

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  • 2020-12-04 20:49
    @POST
    @Consumes(MediaType.MULTIPART_FORM_DATA)
    @Produces(MediaType.TEXT_PLAIN)
    @Path("submit")
    public Response submit(@FormDataParam("clientID") String clientID,
                       @FormDataParam("html") String html,
                       @FormDataParam("pdf") InputStream pdfStream) {
    
        try {
            byte[] pdfByteArray = DocUtils.convertInputStreamToByteArrary(pdfStream);
        } catch (Exception ex) {
            return Response.status(600).entity(ex.getMessage()).build();
        }
    }
    
    
    ...
    
    public static byte[] convertInputStreamToByteArrary(InputStream in) throws IOException {
        ByteArrayOutputStream out = new ByteArrayOutputStream();
        final int BUF_SIZE = 1024;
        byte[] buffer = new byte[BUF_SIZE];
        int bytesRead = -1;
        while ((bytesRead = in.read(buffer)) > -1) {
            out.write(buffer, 0, bytesRead);
        }
        in.close();
        byte[] byteArray = out.toByteArray();
        return byteArray;
    }
    
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  • 2020-12-04 20:57

    sample program to upload file using jersey restful web service

    Require Jar Files (download from Apache site) : commons-fileupload.jar, commons-io.jar

    package com.sms.web;
    
    import java.io.File;
    import java.util.Iterator;
    import java.util.List;
    
    import javax.ws.rs.POST;
    import javax.ws.rs.Path;
    import javax.ws.rs.core.Context;
    import javax.servlet.http.HttpServletRequest;
    
    import org.apache.commons.fileupload.FileItem;
    import org.apache.commons.fileupload.FileUploadException;
    import org.apache.commons.fileupload.disk.DiskFileItemFactory;
    import org.apache.commons.fileupload.servlet.ServletFileUpload;
    
    
    @Path("/UploadTest")
    public class UploadData {
    
    
        @POST 
        // public String upload(@Context HttpServletRequest request, @PathParam("myfile") String fileName) throws Exception {
        public String upload(@Context HttpServletRequest request) throws Exception {
    
            String response = "none";
    
            if (ServletFileUpload.isMultipartContent(request)) { 
    
                response="got file in request";
    
                // Create a factory for disk-based file items 
                DiskFileItemFactory  fileItemFactory = new DiskFileItemFactory();
    
                String path = request.getRealPath("") + File.separatorChar + "publishFiles" + File.separatorChar;
    
                // File f = new File(path + "myfile.txt");
                // File tmpDir = new File("c:\\tmp");
    
                File destinationDir = new File(path);
    
    
                // Set the size threshold, above which content will be stored on disk.
                // fileItemFactory.setSizeThreshold(1*1024*1024); //1 MB
    
                // Set the temporary directory to store the uploaded files of size above threshold.
                // fileItemFactory.setRepository(tmpDir);
    
                // Create a new file upload handler             
                ServletFileUpload uploadHandler = new ServletFileUpload(fileItemFactory);
    
                try {
                    /*
                     * Parse the request
                     */
                    List items = uploadHandler.parseRequest(request);
                    Iterator itr = items.iterator();
    
                    while(itr.hasNext()) {
                        FileItem item = (FileItem) itr.next();
                        /*
                         * Handle Form Fields.
                         */
                        if(item.isFormField()) {
                            response += "<BR>" + "Field Name = "+item.getFieldName()+", Value = "+item.getString();
                        } else {
                            //Handle Uploaded files.
                            response += "<BR>" + "File Field Name = "+item.getFieldName()+
                                ", File Name = "+item.getName()+
                                ", Content type = "+item.getContentType()+
                                ", File Size = "+item.getSize();
                            /*
                             * Write file to the ultimate location.
                             */
                            File file = new File(destinationDir,item.getName());
                            item.write(file);
                        }
                    }
                }catch(FileUploadException ex) {
                    response += "Error encountered while parsing the request " + ex;
                } catch(Exception ex) {
                    response += "Error encountered while uploading file " + ex;
                }
            } 
    
            return response;
    
            }
    }
    
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  • 2020-12-04 21:01

    You could store the binary attachment in the body of the request instead. Alternatively, check out this mailing list archive here:

    http://markmail.org/message/dvl6qrzdqstrdtfk

    It suggests using Commons FileUpload to take the file and upload it appropriately.

    Another alternative here using the MIME multipart API:

    http://n2.nabble.com/File-upload-with-Jersey-td2377844.html

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