PHP how to get the base domain/url?

Question

function url(){
    if(isset($_SERVER[\'HTTPS\'])){
        $protocol = ($_SERVER[\'HTTPS\'] && $_SERVER[\'HTTPS\'] != \"off\") ? \"https\" : \"http\";
    }         


        

Answer 1

Shortest solution:

$domain = parse_url('http://google.com', PHP_URL_HOST);

Answer 2

Step-1

First trim the trailing backslash (/) from the URL. For example, If the URL is http://www.google.com/ then the resultant URL will be http://www.google.com

$url= trim($url, '/');

Step-2

If scheme not included in the URL, then prepend it. So for example if the URL is www.google.com then the resultant URL will be http://www.google.com

if (!preg_match('#^http(s)?://#', $url)) {
    $url = 'http://' . $url;
}

Step-3

Get the parts of the URL.

$urlParts = parse_url($url);

Step-4

Now remove www. from the URL

$domain = preg_replace('/^www\./', '', $urlParts['host']);

Your final domain without http and www is now stored in $domain variable.

Examples:

http://www.google.com => google.com

https://www.google.com => google.com

www.google.com => google.com

http://google.com => google.com

Answer 3

This works fine if you want the http protocol also since it could be http or https. $domainURL = $_SERVER['REQUEST_SCHEME']."://".$_SERVER['SERVER_NAME'];

Answer 4

Use SERVER_NAME.

echo $_SERVER['SERVER_NAME']; //Outputs www.example.com

Answer 5

You could use PHP's parse_url() function

function url($url) {
  $result = parse_url($url);
  return $result['scheme']."://".$result['host'];
}

Answer 6

Please try this:

$uri = $_SERVER['REQUEST_URI']; // $uri == example.com/sub
$exploded_uri = explode('/', $uri); //$exploded_uri == array('example.com','sub')
$domain_name = $exploded_uri[1]; //$domain_name = 'example.com'

I hope this will help you.