How to get Device UDID in programmatically in iOS7?

Question

How to get device UDID in programatically in iOS7.[[UIDevice currentDevice] uniqueIdentifier] I was used this code This is deprecated iOS7. how to get the devic

Answer 1

In Swift you can get the device UUID like this

let uuid = UIDevice.currentDevice().identifierForVendor.UUIDString
println(uuid)

Answer 2

It's work 100% to all the version

other best option recommend by apple use ASIdentifierManager Class Reference

ios7-app-backward-compatible-with-ios5-regarding-unique-identifier

this link tell you how to handle and use custom framework

uidevice-uniqueidentifier-property-is-deprecated-what-now

iOS 9

NSUUID *uuid = [[NSUUID alloc]initWithUUIDString:@"20B0DDE7-6087-4607-842A-E97C72E4D522"];
NSLog(@"%@",uuid);
NSLog(@"%@",[uuid UUIDString]);

or

it support only ios 6.0 and above

code to use [[[UIDevice currentDevice] identifierForVendor] UUIDString];

NSUUID *deviceId;
#if TARGET_IPHONE_SIMULATOR
deviceId = [NSUUID initWithUUIDString:@"UUID-STRING-VALUE"];
#else
deviceId = [UIDevice currentDevice].identifierForVendor;
#endif

ios 5 to use like

 if ([[UIDevice currentDevice] respondsToSelector:@selector(identifierForVendor)]) {
    // This is will run if it is iOS6
    return [[[UIDevice currentDevice] identifierForVendor] UUIDString];
} else {
   // This is will run before iOS6 and you can use openUDID or other 
   // method to generate an identifier
}

Answer 3

UDID is no longer available in iOS 6+ due to security / privacy reasons. Instead, use identifierForVendor or advertisingIdentifier.

Please go through this link.

   NSString* uniqueIdentifier = [[[UIDevice currentDevice] identifierForVendor] UUIDString]; // IOS 6+
   NSLog(@"UDID:: %@", uniqueIdentifier);

UPDATE for iOS 8+

+ (NSString *)deviceUUID
{
    if([[NSUserDefaults standardUserDefaults] objectForKey:[[NSBundle mainBundle] bundleIdentifier]])
        return [[NSUserDefaults standardUserDefaults] objectForKey:[[NSBundle mainBundle] bundleIdentifier]];

    @autoreleasepool {

        CFUUIDRef uuidReference = CFUUIDCreate(nil);
        CFStringRef stringReference = CFUUIDCreateString(nil, uuidReference);
        NSString *uuidString = (__bridge NSString *)(stringReference);
        [[NSUserDefaults standardUserDefaults] setObject:uuidString forKey:[[NSBundle mainBundle] bundleIdentifier]];
        [[NSUserDefaults standardUserDefaults] synchronize];
        CFRelease(uuidReference);
        CFRelease(stringReference);
        return uuidString;
    }
}

Answer 4

Swift 2.2+ proper way to get UUID:

if let UUID = UIDevice.currentDevice().identifierForVendor {
  print("UUID: \(UUID.UUIDString)")
}

Answer 5

Have 2 solutions:

• You can use identifierForVendor after that store them to keychain and use later. Because value of keychain will not changed when re-install app.
• You can try OpenUDID

Answer 6

For getting UUID in Swift 3.0:

let UUIDValue = UIDevice.current.identifierForVendor!.uuidString