How to solve for viewpager : The specified child already has a parent. You must call removeView() on the child's parent first

Question

Into my project I am using viewpager with three tabs named History,Main,Map.Main activity contain Timer,stopwatch,etc

Answer 1

Here's my solution (used in each of the fragments) , which allows both smoothness and avoids memory problems:

...
private LayoutInflater mInflater;
private WeakReference<View> mRootView = null;
...

@Override
public View onCreateView(final LayoutInflater inflater, final ViewGroup container, final Bundle savedInstanceState) 
  {
  if (inflater != null)
    mInflater = inflater;
  else
    mInflater = LayoutInflater.from(getActivity());
  View rootView = mRootView == null ? null : mRootView.get();
  if (rootView != null) 
      {
      final ViewParent parent = rootView.getParent();
      if (parent != null && parent instanceof ViewGroup)
        ((ViewGroup) parent).removeView(rootView);  
      }
  else 
       {
       rootView = mInflater.inflate(R.layout.fragment_test, null, false);
       mRootView = new WeakReference<View>(rootView);
       }
  return rootView;
  }

Answer 2

I have also faced this problem.

You can solve it by just add single line mViewPager.setOffscreenPageLimit(3);

public class SwipeyTabsSampleActivity extends FragmentActivity {

...

@Override
public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);

    setContentView(R.layout.main);

    mViewPager = (ViewPager) findViewById(R.id.viewpager);
    mTabs = (SwipeyTabs) findViewById(R.id.swipeytabs);

    SwipeyTabsPagerAdapter adapter = new SwipeyTabsPagerAdapter(this,
            getSupportFragmentManager());
    mViewPager.setAdapter(adapter);

    mViewPager.setOffscreenPageLimit(3);  <------  Add this one
}

}

Good Luck.